3473-11 Exam 1 solution

3473-11 Exam 1 solution - Name CHE 3473 Chemical...

Info iconThis preview shows pages 1–12. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 6
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 8
Background image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 10
Background image of page 11

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 12
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Name CHE 3473 Chemical Engineering Thermodynamics September 15, 2011 Exam 1 100 points I Print your name at the top of each page. 0 Open book, closed notes. One 8.5 " x 11" piece of paper with anything you want on it. I 2 hours 0 12 pages total 0 Cell phones must be turned off and stored out of sight. I Use your time wisely. Make sure you allow time for each problem. 0 State all assumptions. 0 All work must be shown to receive full credit. 0 Good luck! Put your name on your note sheet and submit with your completed exam. Page 1 of12 “W E \ we Name ‘32- m‘ffim kflg f Short Answer (29 points total) Answer in your own words, no credit for direct quotes from our text, handouts, or notes. 5 pts What is the defining feature of an “ideal gas?” Aw. iciaui am eg-LgL‘i'x M3 M‘Lfid‘m'li'ian Eeriw 196M miamier, 5 pts What are the three requirements for a vapor~1iquid mixture to be in equilibrium? L Time (aw-€39“? mi“ 4L2 M‘if‘flgce Lgiwtéfim ~in PM; {5 "Ha mm; m BG‘I‘L flaw, ; Meeéamfii @ij-i.‘Lrium’ M ARM/2:3 algae Qty} a) flVEL'iN‘ \rg Ifiimifi‘i “M0” 2. Th impmiwe, i; 4h Mme M Lei-[n (Dimer. #J/xerml a wlaLn'umJ 45 driviflé £0e\ gr ng‘i" 3. TLQ QLeMECGi ’Dfl‘ifin‘fiw!fiif 590 6'1 Cam/(951199;? me We Sam M Qa—iL pLGSes m cloak/g Qrca age “Hemor- dl‘EMIIMF 7%, nei‘ immlér 015 my d‘é’wflnwi Lgiwma [ohms L's" 39:3 Page 2 of 12 Name gnlm‘l'ion Ki? 3; . 1' Short Answer - continued 5 pts Most car engines use circulating water to remove heat from the engine block. The warm water goes to the radiator where heat is transferred from the water to the outside air. Can the heat transfer from the radiator to the outside air be considered a thermally reversible recess? Ex lain wh or wh not. p p y y 4:19 on Wfiilht'lr‘flf' 4'0 when“: lied-(ind; /' ' ’ Mylar“ 793/74 1‘ ewj'flt‘; “*3 Cfiolw/ We‘lEr to HAS/ta ElmcL stack ~ Mt)? Air (:3 armhol- “lth xv EO‘F Nb, ll“; loll “laugh? (army [J nrrl‘ Inca/rifle. The driving efforts. [I'LENFPFCMLWB allmrenca {gelwmn Mr (S‘M-rmmfltn‘jfl and “Jaimie! m)] l} nn‘l' anAtEl'ESthMa-ll/ Small,- A—G‘flsgr “54L 3* £443 49”"!{3 D’tm'r'ncfi . . \ l ‘W one :My L‘fi archwte Conceptual; Nina fafio‘l @va‘flf. {Aka k mm W38 5 pts What do we mean when we say internal energy is an inferred property and enthalpy is a defined property? 7L8 ,sy’xxl‘mce, no la‘lerml 94454-57} bl) is ‘ ingrrfigf H filichle "Prom Jfltg l£+ Lflwt magi, at a alter w} Lr a Meal 4W” Wm (ll-Web», l‘le't-PU, M MRS Cfltaileal 'M {Jeri— ‘iD $\‘r\t0lJ; Gnayrlg 65D SF?“ S/fljfi‘flrg. Page 3 ole Name Sol Wks q EEK Short Answer - continued 5 pts The purpose of a heat exchanger is to transfer heat (Q, Btu/hr) between two streams. However, the “Q” term in the is1 Law analysis of a double-pipe or shell-and—tube heat exchanger is typically assumed to be zero if the heat exchanger is insulated. Explain this apparent contradiction. Include a diagram with your answer. ,_ ~— -—- —~ ._. K (“M Syslcm [00*“(157 0L} ‘QLW 0.67M: / I I I A' ’ \ 1 [WI \ HOST 5403mm Ou‘i’ 6‘4—W—_‘.—"W‘!{'—’— Sliffiam in l \L Q“, if i Cold (Angus. I Hi I ,- r‘ Chlai 5;“?an UVel' QIGVLNJ U}; [firimu _....-. Hm huh Embcnber‘ all}.in 6:)“ng b4 fiD’l“3E€rO Ciro! {‘9ng #0. (mfg; MAMA ’90,... ll“, fol :lw-eom in Me Cuts! fittest, We hat—l 4mmer art-LN! (Engaged well!” a; “3L Law Amefivftfi M an idealisle hand QYLLIANL r lg am; a: alert :1: M Lu} [arr or "m’a dfismrx‘SL lie iAgmlfi‘iw‘o’t (Egslem Qahmle?\ 2 pts Identify 0 specific concepts or ideas that have been discussed in class that you aren’t comfortable with or don’t fully understand. One or two word answers (e.g., entropy) are insufficient as they are too general and don’t help the instructor understand what needs to be done differently in the future. /. M Z N 2 pts Identify two specific concepts or ideas that you now understand that were unclear, vague or misunderstood at the beginning of the semester. Page 4 of I2 Name St: )MJnEDv"! Keg-x .___.—..7___~ TRUE I FALSE - 3 points each (15 points total) Circle T or F to indicate whether the statements below are true or false. T = True; F = False l. T Flow through a heat exchanger is typically characterized as isentropic. FEW 4'1"” 0: I1 94' Q XLENEJASPF E5 LJE’J‘; raj “ nDfl-Q0keLcjfit ahfidém “ n w ( its“). lff‘El/GH‘ CHE) IR! film) Pic lo 0 is aplt'alsa‘lif; ad 0’ we me la . 2. ("1) F The entropy change of a system can be negative in numerical value. figfyflm + £3 ggu‘fmhdmjj' Z O [ 12M rifler Wallet“) = ’C Cfih [99 Ch} 3. T ® One hundred percent pure water is an “ideal liquid." {Am figs/«‘01 I'S I‘4C0meAQrile avgf I‘AUl‘J‘cf‘a/ ('2be Uums'rly) 4. T IOGA is an acronym for “ In —- Out = Generation Always” "II/IF“; ” Bud‘le f‘ QDHE‘Ffil—kfln '5 Aficumwlq‘l‘lm 1.0 °R PM?» WU'YJM/ ZVCI‘EM.‘ Egret/dig lmsw yd“ “fl—“(FrEF ‘Mt Sinleméa+/ CA“ La £1waun +3 Eiltlxef "l‘flt‘, er" Alspl 41m 3". AT => lE’F = IOQ Ash,th T a» I“? r 46%? fig Page 5 of12 Name Problem 1 - 18 points \ Water is flowing at a constant rate through a horizontal, perfectly insulated pipe shown below. The water remains subcooled with firlly developed turbulent flow at every point along the flow path. The water can be assumed to be incompressible. Insulated Pipe P2! T21 LIZ U2! H2! 82 Afimlmlfi Sabina/x flaw at an imCOMfrP-Ui-Lfc fluid Fill in the blanks below with “>, =, <, or '2” indicating the relationship of the physical property at location 2 to that at location 1. Explain the reason for your answer. Answer in a rigorous fashion. That is, do not treat small magnitude effects as negligible or zero. Reason P2 < P1 ?rer5w‘e Girof" l5 fpl‘ic/‘inu/L [0.5593 pressure T2 > T1 Time, imparts r5, :3," Mr, i: gig-W7 higher“ temperature orgasm? Hum-t 4L9, Mia; white in MM, EM?eg Misfit—km QJSDCwiepl mil 4L3; file‘th Miufis, M 112 velocitym TAB “Ho-TL WJUCCJ7 Smaller J/Lm wepvnr glialx‘rl 3 rile Mle Wei-0154L (2..) MM. Obi/6+1; '1 flat LZ OZIOWI-gg I555 “Jr iii—lie {gr/(Vie ‘L‘D vile, 'i—qupemlmrg, «MW ‘ Ma CfiMcichr" {AW/AH: {humid Campfi/ £7 we‘lbij‘aq, wreak m 2/91 well: cam-l7 own a re ml at M also: If p2 < p line“ 7 MEMWEMEW‘" glam-cm NC'll/tifi/ AU; lee able “it! fl/é’ fir. For all mm; [OM/Jarej/ lie Verbal; our? ML>Ml ‘ P efiof 2 r ‘ _. I I / WWW E0 4 9 Jami” 5‘5 '“ 5“ "Mt: ammw/ :r MCOWWWJrLP. Sofh‘kfla a“ m » Name 1”; Law! gr" ficenpffl¥fgw 653*"ka Lam‘+%fi* Es\';‘143 i Q" “)5 ' AUPML; Problem 1 — continued Ir 1 . Reason £“SV‘1‘L‘Z‘, E‘Pé‘ Ctgg[rkl:\atul?_ or; kma'éfik “m” 7 _U2 ‘ U] M L; C ‘RWLg/L of T [Rmp( qt) ‘ TLC. lutemal energy [51,) B (Mgch . 2E ‘ @EVME 3:13 419m? Em:de “RNA mtfliwg (/f } [owl— Jig 0495’3‘36 M :Qr any Mme" “3‘1 P W‘tfhlpl Harm: H. Tim “Pf/N5? “fig” We“? j“ M} @U'EPLM‘ Ve‘ou‘rl] i; adal‘eum’ “I'lnr‘bna‘fl a2 “Mfutfim m PAPWK‘?! Wflrj . Th1 GALE? ermgvd- Mékflf D’tflfich‘ ,Mmem‘m‘ 1x «fir IM‘CWLM fine-\‘thl/ 5D Wzfirjfl ,Lo H2 :‘ H1 “h\\ H4 pref-mm clan/9» mg! Va?er EIHLT‘” charm? piewflflfi. entl—l-zpflpy NEGL ("fl-“Ml 0h fly. W W mm,“ Mm“; {171 L: UBPyJUer Ale kafli WAC, QQL‘DLQEI'W [M [WILL ‘lr‘MFJPA, ’15 5‘9,va {MS 4k“ 14" “Pm-$04 chafie. m2»: M1, MW“ H1: H—t ' 1p AM 4‘5 W" (/1; ts reajrer Ham 0L (9): 0.0000055 92" 41¢ 13an Lg Cihje If Q‘s-M55119? 3mm” (“£413. Howmgr W37 \ WNK fin? {airfare in final»; Emil}; MMJL Lg Ofi" fl“ 2 enfl'OPy I _ R 6hr??de Vt)! GEE-(“Brae :Lx @QILJ 413 5:24“ l Law ,| N_WWWUIWWM"wwu—aawuwuwm—WWWW-~~-~w—~--w»~—,~—.m..m__w,_m“WWW TLC for; GJD-r‘c. glue, #0 agichaa ;P/‘w/Mcw p now—«Egalbkko {acer ‘M 9&0. l a I; (Am. }r‘r‘eucr,rl(=f¢ FKDQ‘ZS'L Page 7 01°12 Name Problem 2 - 18 points Superheated steam is flowing at a constant rate through a horizontal, perfectly insulated pipe as shown below. The steam remains superheated with fiilly developed turbulent flow at every point along the flow path. The steam cannot be treated as an ideal gas. insulated Pipe P2: T21 U2 U1: H1181 U2. Hg. 82 Agii'aiaxdsc 'ii‘l'e‘iion Gums 6D in com/)rg;5'.$\e liar-d Fill in the blanks below with “>, =, <, or ‘2” indicating the relationship of the physical property at location 2 to that at location 1. Explain the reason for your answer._ Answer in a rigorous fashion. That is, do not treat small magnitude effects as negligible or zero. Reason P2< P1 ?Fesrnm gimp i; d—Smbdniaie 7% UGia‘i-iom (omit. pressure Tilere 0J9 ’iwo Flemming bunny—{8. m (walla! [madam a rtE‘i “lemft’rndw dam-are. The o'ch mascot {a} :Clow i5 dUfi/ched T2 < T] a; lléc‘i' and QE‘C! ~41; morgue lira filw‘d ‘iC—‘Wfifia‘iwe, iii'pmuft‘, temperature \{lu‘r [Impl- ir mutL Swallcor M m V‘H‘ME’ “flair Jinn, ‘iE’m/O {Ga/Mg‘iim wheeled #0in 44¢ CDnUECfioa ob m {Mai (M957 43 iii/«ELL mgr Tie Safarimiafl Sigma @x/Dmdr Ma/ acre/Praia m “Wm. rare-mute oimff dhe, i1 Tie snag/v Neal 41) melee-lg r ~~~~~~ “mam ‘Me finial is {Wham 97 tie "AWN 9M5} 0b “‘9 “aim” ul m : FmAt =— Cofll’im‘i‘ velocity We. Clamfl‘iy Oiec'mw Aims lie Rm 531M 4‘ 41‘: alpine-inn i-x (comm. Tb martial-4 a CC; “with mam film twig? wile H‘elocci/ afi JFLQ gurppflcfilmf glam Mari Mamie Io lLs-l— flu WMM (MS; mi. Page 8 01°12 Eff Law fii‘ar gem} .. FEM $515an M A Kwdmafiflg = Qws - gawk A [fiJ-fi-"é—FM14-EX v-—--._-..__|_H Problem 2 -— continued 0 r ‘7 &3% 3 Q JIM"? /W“ $35;th Lg)de t ® flir- lg‘" LAW am(y§i§ a ., - — Insulated Pipe P1'T1' U1 P2. T2. “2 U1. H1. U2. H2! Q = “‘5 "e 51:3"; = 0 floor- A’Lu ngwtn.‘ Reason u 7 U iniemal enereg 3096M { car" Jfl‘enj Junwfon. if; LOH NEW??? 5367mm Sela 1/: am: + tag ,1 -.- w/Wg 5A- Mlnpwz ow ‘rbbr W7 “5ch Jr!) 44rd: Zwflha HzennfalpyH‘ hm “M “W W La “5% (8.1.: MM 4o alek WRAP? 41‘ 6‘ cuL +Le QIQH- harm; in Isaak; Ewarjf may 7% PRFQ, ARM :u‘m] 2 0 32 > s. A I 1 4% A" entropy Te [ML bum-r. due Wham“ romaéflg a “DH‘MJBMC Mcme it TM is an. ErfeuerJlLlc fracas“, Page 9 of 12 Name S0 i L‘PL‘O/l Problem 3 - 10 points Trace the following five step process on the Ethane PH diagram on the following page. Mark darkly so the path is clearly visible. Fill in the table below with temperature and pressure at the end of each step. Starting point Saturated vapor ethane at 50 psia Step 1 Constant volume transition to 160 °F “ 7m '0‘“ 1‘49 0b fflflgfll" Ole h5‘47 Step 2 Isenthalpic transition to 1,000 psia — llaw like afi‘ cans-Edi ovul'Lch/ Step 3 Removal of 115 Btu/lbrn of energy at constant pressure *— ‘Djllfl as liq UVLFlk-Cl‘ PP Step 4 Isothermal transition to 10 psia - pallm line, 0A (,0 7" Step 5 Isentropic transition to 100 psia h {30”th [m 5b comical, _ Temp, °F Pressure, psia Starting Point " 80 SO End of Step 1 I go g:- End of Step 2 3-37 5950 End of Step 3 l 20 If 0® End of Step 4 {20 [0 End of Step 5 320 [00 Page 10 of12 £35 Sflmficm § , A, W 1“ “55:38 Emu 2m .n. .1 £me 3:232". 09. ‘eunsseJd O O ,_ BlSd Door oooor Page 11 of12 Name 50 1a,, Keg: Problem 4 - 10 points Ethane at 162 °F and 1,000 psia is flowing in a pipe at the rate of 10,000 lbm/hr. A valve in the piping network has been left partially closed and the ethane experiences a large pressure drop when flowing across the valve. The temperature downstream (after) the valve is 40 CT. The temperature of the surroundings is 80 °F. What is the lost work (hp) associated with flow across the valve? The PH diagram for ethane on the previous page may be useful. Clearly state any assumptions associated with your answer. \ (EM éyfilcm llQDurdm Elias m 1 [(91003) “5"? P” M 2/ 7’?- Imsm a ZI><II W Pa"? .u— " ~- r ’(I an 1 0‘ 7-1: lE'L'lT [z 4- F iwmwgllfls 1 hF "TC; v (go anagram}? : gnaw Aflom‘dmle flew a:ch value 5:5 ifctiLlPEQ slime. we have r'mQ fgjeegr‘fi ‘l’ie lam: fifth (firm/leg! “lb Cfillcmloch Who'll? mfil OMGFMCIE LEWIS-C 9W6; chattel, I C}, no V” flfiwgv- £5 Pm 9&1 5:41 (If t. £14» 92/: '30er mm [pow/([7 ' a A, D 0 an all. hung/vital “Chagall Slat T3 a All: 0 :> m at awn +1.: 450 75:: ml Sr 093 le‘F' M25?" 4&3 $39»: 1:5 P2 1' {99 FT .r-w‘l = 4+0“? 'SL 3- LCA fir“ on (We «133 tr ms?” (“W W Page 120f12 ...
View Full Document

This note was uploaded on 10/11/2011 for the course CHE 3473 taught by Professor Staff during the Spring '08 term at Oklahoma State.

Page1 / 12

3473-11 Exam 1 solution - Name CHE 3473 Chemical...

This preview shows document pages 1 - 12. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online