Exam 1 KEY - Questions 1 — 5 (2 Points Each): Select the...

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Unformatted text preview: Questions 1 — 5 (2 Points Each): Select the correct name or formula for the following IONIC compounds: C k l on Are Question 1 (/ L+ Hg2(C103)2 Clo; xL= -L :‘1 Hal : mauve, (3:) a). mercury(I) chloride I c). mercury(II) chlorite ‘ b). mercury(II) chlorate Q» mercury(I) chlorate (/ Alec Hue c 144‘“ Question 2 _ q * rhodium(IV) cyanate C ‘1 NW” ‘- N W K [\Ddiam (III) 1 (LL R A/ an; ‘1 a). Ru(NCO)4 @ Rh(NCO)4 L WWW MWS b). Rh(NCO)2 d). Ru(CN)4 Question 3 ‘ ' - - l ‘3 - 0130,04» CJ- MJMWM) All/VHS + 1-7 M +1 ‘ ,LI, 3 foq ‘ prowl/Wt ) No (AM/UR Mad 1‘ x. a). cadmium(II) phosphate @ cadmium phosphate r f, ee 57° C c: Nu! ’” 71x6 M M b). cadmium(III) phosphate d). dicadmium phosphate Q Question 4 g — chromium(III) sulfite C a + - Elwyn.“ (In) SUlFfre = S of a). Cr(SO4)2 @ Cr2(803)3 1x Lg + : +4 L~ E ULIUDJ) b). Cr2(SO4)3 d). Cr(SO3)2 9 x f0} : ‘5 7 Question 5 Ir2(8203)3 Wmlr—m z 510:- $3 : ‘L =\ TWO ilziéiuAg : +5 / 1 + @ iridium(III) thiosulfate c). iridium thiosulfate L a he b). iridium(II) sulfate (1). iridium(IV) thiosulfate Questions 6 — 10 (2 Points Each): Select the correct name or formula for the following COVALENT compounds: Question 6 A8204 a). arsenic(III) oxide diarsenic tetraoxide Question 7 iodine pentachloride 105 b). 1(c1o3)5 Question 8 P235 a). phosphorus pentasulfide ® diphosphorus pentasulfide Question 9 dodecene Question 10 (37le a). heptene b). hexyne 7.: A; Two: A; F0u&:1\e,w c). diarsenic hexoxide d). astatine oxide PM A»: L- C). IC13 d). 0151 §=fwM c). diphosphorus sulfide d). pentasulfur diphosphide d°dtc=11~ fl C C)- C12H22 ~ Que $153145? ChHU‘ l1 HlLl d)- Clono Questions 11 - 15 (2 Points Each): Select the correct name or formula for the following acids: oucSfiO” 11 P0 3': Pl/xofplv‘rt =5 *I‘TQ 4~iou = -our 4a; H3PO3 3 a). phosphoric acid c). hypophosphorus acid @ phosphorous acid d). hydrogenphosphoric acid Question 12 . HClo Clv‘: “we chic/Lire =3 fire Amour \ ow Aug a). chlorous acid c). perchloric acid b). hydrochloric acid hypochlorous acid Question 13 Hydrobromic acid a) HBr c). HBr03 b). HBrO d). HBrOz Question 14 Iodous acid ~ OUS‘ A‘C-‘ol '- ‘l‘fl Ml‘ofl =3 {0 dire ‘- I 0,: =\ H 101 a). HI c). H10 @. H102 d). H103 Question 15 Acetic acid A CQMQ ’- (L HA 0; @HCzHgoz c). HAtO; b). HNCO d). H2C03 Question 16 (7 Points) The element rhenium can form six different oxides. If 1.930 g of rhenium is reacted with dioxygen to yield 2.179 g of an oxide RexOy, what is the molecular formula of the oxide? a). R602 @Rezo3 AMOu/v'r oF Df-yfiuv; ‘I ‘ . _ b).Re03 d).ReO arm; I ‘1307- 0100‘? Mold 011 ).q395( Mos g 0 0 Mom F_ : W «- . ° . Mo, 1 m 1501073) N M o 0 m.) Ma 0 . .o ISLO- 0 Question 18 (7 Points) AH“? " m3: 1" ti—l'u “— Raj); The tetra-saccharide stachyose has an empirical formula C3H14O7. If the molecular mass of stachyose is 666 g/mol, what is its molecular formula? EMff/Lim WV 14 U’el‘opq a). C15H33028 0) C32HS6028 . PM (H.107 = 111177,“, b). C48H2303o C24H42021 L N be: Mel «C _ o U W 1 w \ “57/41.. ’3 MOl'CVLl/t FOAMJH: Nab/L EijkicH Faun.” . {kl [he :3 ({- qum, 7 I 3s: 3H“ 07) : Cu Hg 0 Question 19 (7 Points) L 11 Calculate the energy exerted by a 5.250 ounce baseball travelling at 102.3 miles/hour.~ E ; _)i M U 1 a) 155.6 J c). 20.70 J _ _ O Wer ~ 5L5“;L m UK b). 34.00 J d). 321.5 J We) ' L = 0.112309 3” M/r k ~17; 1W l°°"‘1 Vase?»1 ; ’91,;M;( M ) FIXOFT.)(ll:~)(/E£‘lcq)(_i):qgj3M/f 3‘00: L 1 911m -. :(0.Imn~q)(us.7wr)‘-155.43 _ Question 20 (7 Points) Convert 3.194 x 108 1b mi2 h'2 (where lb = pounds, mi = miles, h = hours) to dekajoules (daJ)- , . [It [\lI—‘ILML a). 6.475 x 108 daJ @1895 x 106 daJ S l c).1.042x1010daJ d). 7.002 x1012 daJ ' <44 3 = (0 T . '1 9. .451 $1075 )1, M. 1n.) rump? {Fwy 1.91% I .M )1 .L‘ l flfy . lF-r l 1N loocM L, 2.1% H, I M- . 3600; W 0F NU‘Q QXPAU‘Noyr New! To Re You/pad. T = 1.50:: x10‘ m : 1.7mm? L7» ‘57 : Z'WKHN Question 21 (7 Points) The density of lead at its melting point is 10.678 g/mL. If a sample of molten lead occupies a volume of 3.672 hL (hectoliters), what is its mass in nanograms? a).3.429x10‘3ng c) 3.921 x 10%;; b). 2.924 x 109 ng d). 1.971 x 1018 ng 3.671 M. IODL [100021) 10.673j)(__’_’2_\ I Bflhxwwm [M ‘1' ML mo*% :7 Question 22 (7 Points) A sample of eicosane C20H42 contains 4.347 x 107] molecules. What is the mass of this 1 ' ? sampemmegagrams QMW: 23))..gS-7/MG‘ a). 7.396 x 1091 Mg c). 2.555 x 1039 Mg Q.) 2.060 x 1044 Mg d). 7.396 x 10103 Mg Ll, 2W7flb7'MfilCLUlV(/L:?L——N ) [ Ill/l1 13 x \——~ 4.01.1] 5L“) MolECU‘Kr Ms; IgIOL—j ) : LOHOxlo'lUM Question 23 (8 Points) 3 Perform the following mathematical operation and answer with the proper number of significant figures. A10 Dec-‘w\ \ (9.4211102 + 8.234x102 + 1.625x103) : WU $8.9 + '4 Lg) 3.12152 2 JD a). 1086.1 c). 1.00x103 / 440 0.0”, b). 1086.14 1086 = NDIOfi P$V4'I°w . 5" F; 3 [ngL 7 l! F \ é $1.3 [11.75 ‘~ 10%. H7: Comp/u; om», C / L1] 1%) 0 Question 24 (8 Points) New To AM A compound is 66.01 % carbon and 7.21 % hydrogen by mass. The only other two elements present in this compound are zinc and oxygen. A carefully controlled oxidation of 0.2145 g of this unknown produced 0.0480 g of zinc oxide (ZnO). What is the empirical formula of this unknown? @ 0201202le c). C6H1303Zn3 C24H3203Zn . d). C14H17O4Zn2 0 70111071111: ; moneyaovsmw 0.0231300 ‘MTBTM o.»zmj.,.r:.:“00 137003v444m loo~l£.01~711-17.11 = 75.910 7. 0 ‘ ’7'717o%~ 3)V>11007erle/7q—mw:3 Lbowjfl 2 Mo! :7 ISM.‘ 2" lL-OWM" C 1,0075%; ‘ K = 17; ‘1) Moll ll/H‘io H (S'377/Mu1 Mlivv 55° “:25 0L?“ 3W”; *7 c H o ' “‘02” ° 07?; 0.173 0.175 0.11s“ 1" LL 1%” Question 25 (8 Points) A certain element has four naturally occurring isotopes, as shown in the table below. Isotope Atomic Mass Percent Abundance E-123 123.197628 g/mol 46.77 E-125 124.968902 g/mol 24.67 E-128 128.017238 g/mol 12.57 E-130 129.992344 g/mol I S. ‘10 Calculate the average atomic mass for this element, which is the atomic mass you would find under its symbol on the periodic table. a). 104.54 g/mol c). 126.18 g/mol C»? 125.32 g/mol d). 116.45 g/mol Avmfimwlmfi(ILB'IQWéLEXO~‘1L7‘7)+ ['Ul.0|63°(07,¥ 019(27) + {Mosz 0.11573UL‘121231‘1X D~ 197°!) : gjlém130.37;°\b+16.0j17+10.7§§7 : Question 26 (8 Points) An unknown compound contains only carbon, hydrogen, and nitrogen. The combustion of 0.1754 g of this unknown results in the generation of 0.5298 g C02 and 0.1084 g H20. What is the empirical formula of this unknown? 0W1” 0F UH . HN . a) C18 9 c) C2H2N13 0.415183 (0L({L.o|q( ) : 0.1‘4‘1S7L C4H9N2 C9H9N 6' f LOL 0.10% [i 9 Lou, - 2.) Man“ walla 0.!‘1‘45 L 7 2‘ 7H )~0.01U%7H ~——-—-—-2—-\. woo 0.0m; H 18°17HL9 0,173‘1 7W6-ow Aft“) : $L327.c 0J7‘”7”“”“” = 4.61711 3)1u=lw-grn~LHL=wnozm H)vjctooe"mmpln, Look-Molt: $1.327L 5.36 5.0!].714 s. (LOW/Mu “‘7" ,0 “Incl: 07> 5) Mole - LL ~ .21, H W‘o V" IUDJG‘? : Cfi Hi N 0‘7“ 077111 0 7H Question 27 (8 Points) ' The spacecraft Voyager 1 was determined to be 1.838 x 10'3 light years from earth in May 2011. If 1 parsec = 3.26 light years, and 1.9174 x 1012 mi = 1 parsec, how many terameters was Voyager 1 from earth in May 2011? I TM : ()L ‘ 0 1‘ M a). 18.50 Tm c). 0.2696 Tm b). 4.731 x 10'25 Tm 1.7QbTm 153$ $lb‘31imyw( 1 PM“ Ifln‘wto‘L/fl,‘ QMH ll.” m: (mflwlflfiw M A LN‘ ’74'01LM 1’7‘10x‘0"b~(m Mm )wmwr Question 28 (8 Points) Engineers often use a temperature scale called degrees Rankine (°R), where increasing the temperature of amaterial 1 °R is equal to increasing its temperature 1 °F (so an increment of 1 °R is the same as a 1 °F increment), and a temperature of zero °R is equal to —— 459.67 °F. The temperature at which water exists in all three phases at once is called the triple point of water, which is 273.16 K at a pressure of 1 atm. What is the triple point of water expressed in °R? Q) 491.69 °R c). 186.51 °R b). 555.69 °R . d). 427.65 °R l\ (0N"V/U|’ Te OF HR): UMLLL 273.15 °c = 0.01% m T(°R)=(‘1°Fjr 0.o|°L +31° F: 31'010’: PC Tl°4311°m . o o 5LTPH+L15°L€7 Q _— 91.07. {L 1H57.é7 4 l” :Wnrqm ...
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This note was uploaded on 10/12/2011 for the course CHEM 1414 taught by Professor Slaughter during the Fall '07 term at Oklahoma State.

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Exam 1 KEY - Questions 1 — 5 (2 Points Each): Select the...

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