Phy 102 2005 Exam Keys & Formulae Sheets

# Phy 102 2005 Exam Keys & Formulae Sheets - Dr Huerta...

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Unformatted text preview: Dr. Huerta Phy 102 Sample Final Spring 2005 Spring Semester 2005, Sections S and T THERE ARE 18 MULTIPLE CHOICE IN THIS SAMPLE FINAL QUESTIONS, WHICH ARE WORTH 5 POINTS EACH. In order to obtain full credit for problems 19, 20 you must work clearly and legibly. THE ACTUAL FINAL MIGHT HAVE A DIFFERENT NUMBER OF QUESTIONS. FORMULAE SHEET Vectors: Unit vectors: x-axis: ˆ x ≡ ˆ i , y-axis: ˆ y ≡ ˆ j ~ A · ~ B = | ~ A || ~ B | cos θ = | ~ A | B A = | ~ B | A B , | ~ A × ~ B | = | ~ A || ~ B | sin θ , | ~ A | = q A 2 x + A 2 y , direction of ~ A × ~ B is perpendicular to both vectors by right hand rule. Electric Fields: e = 1 . 6 × 10- 19 C, m e = 9 . 1 × 10- 31 kg, m p = 1 . 67 × 10- 27 kg, k = 1 4 π = 9 × 10 9 N · m 2 C 2 . | ~ E | = kQ r 2 , ~ F q = q ~ E, V = kQ r , | ~ E | = | Δ V Δ s | , Δ V =- ~ E · Δ ~ r, E = σ 2 for a sheet of charge . 1 eV = 1 . 6 × 10- 19 J , U q = qV, KE = 1 2 mv 2 . Electric Field Flux through an area A with unit normal ˆ n : Φ A = ~ E · ˆ n A Gauss’ law for Electric Field Total outward Electric Field flux through a closed surface: Φ closed surface = q inside Potential Energy and Torque for an Electric Dipole: U =- ~ p · ~ E , ~ τ = ~ p × ~ E . Capacitance: Q = CV, C = κ A d , U = 1 2 CV 2 = Q 2 2 C u E = 1 2 E 2 . Circuits: i = Δ q Δ t , V = iR, R = ρ L A , P = V i, P R = i 2 R resistors in series: R S = R 1 + R 2 , resistors in parallel: 1 R P = 1 R 1 + 1 R 2 In a charging capacitor q ( t ) = C E (1- e- t/RC ) , with lim t →∞ q ( t ) = C E , and lim t → q ( t ) = 0 , also i ( t ) = E R e- t/RC, with lim t →∞ i ( t ) = 0 , and lim t → i ( t ) = E R. Forces in Magnetic Fields: ~ F = q~ v × ~ B , ~ F = I ~ L × ~ B , centripetal acceleration = v 2 r magnetic dipole U =- ~ m · ~ E ~ τ = ~ m B × ~ B , with ~ m B = NIA ˆ n Physics 102 Sample Final Spring 2005 Dr. Huerta Phy 102 Sample Final Spring 2005 Sources of Magnetic Fields: μ = 4 π ×- 7 T · m/A field of long wire B = μ I 2 πr , field at center of loop B = Nμ I 2 R , field inside of long solenoid B = μ NI ` . Ampere’s Law: Σ loop B || Δ ` = μ I inside . Gauss’ Law for Magnetic Field Total outward Magnetic Field flux through a closed surface: Φ closed surface = 0 always Induced Emf : Φ = ~ B · ˆ n = BA cos θ, E =- ΔΦ Δ t , E = B`v ⊥ , E = NBAω sin ωt. Inductors : E =- L Δ I Δ t , L = μ ( N 2 ` ) A, U = 1 2 LI 2 , u B = B 2 2 μ Transformers : E s E p = N s N p = I p I s AC currents : I rms = I max √ 2 , E rms = E max √ 2 P AV = I 2 rms R I max = E max | Z | , X C = 1 ωC , X L = ωL, ω R = 1 √ LC | Z | RLC = r R 2 + ( ωL- 1 ωC ) 2 . Electromagnetic waves: c = 1 √ μ 0 0 = 3 . 00 × 10 8 m / s , k = 2 π λ , ω = 2 πf, c = λf, ω = kc....
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Phy 102 2005 Exam Keys & Formulae Sheets - Dr Huerta...

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