Chap_23_soln[1]

Chap_23_soln[1] - 3. Picture the Problem: The image shows a...

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3. Picture the Problem : The image shows a rectangular loop oriented 42 degrees from a magnetic field. Strategy: Solve equation 23-1 for the magnetic field. Solution: Calculate the magnetic field:  52 4.8 10 Tm 0.020 cos 0.051 m 0.068 m cos47 B A   Insight: The minimum magnetic field that would produce this flux would occur when the rectangle is parallel to the magnetic field. 5. Picture the Problem : A solenoid of diameter 1.2 m produces a magnetic field of 1.7 T. Strategy: Multiply the magnetic field by the cross-sectional area of the solenoid to calculate the magnetic flux. Solution: Calculate the magnetic flux: 2 1.2 m cos 1.7 T cos0 1.9 Wb 2 BA       Insight: Note that the length of the solenoid does not affect the flux through the solenoid. 16. Picture the Problem : The image shows a single loop of area 7.4×10 2 m 2 and resistance 110 . The loop is perpendicular to a magnetic field. Strategy: Solve Ohm’s Law (equation 21-2) for the necessary emf. Then insert the emf into equation 23-4 to calculate the rate of change in the magnetic field. Solution: 1. Calculate the emf :    0.32 A 110 35 V IR 2. Solve equation 23-4 for the change in magnetic field: 2 22 35 V 4.9 10 T/s 17 .2 10 m AB NN tt B t   
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Chap_23_soln[1] - 3. Picture the Problem: The image shows a...

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