Chap_25_Disc[1]

# Chap_25_Disc[1] - 25-50 IP Electromagnetic wave 1 has a...

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25-50 •• IP Electromagnetic wave 1 has a maximum electric field of and electromagnetic wave 2 has a maximum magnetic field of E 0 52 Vm /, B 0 15 .. T (a) Which wave has the greater intensity? (b) Calculate the intensity of each wave. Picture the Problem: Two electromagnetic waves have different intensities. One wave has a maximum electric field of 52 V/m, and the second wave has a maximum magnetic field of 1.5 T. Strategy: Use equation 25-9 to calculate the electric field for wave 2. Compare the electric fields to determine which wave has the greater intensity. Then calculate the intensity of each wave using equation 25-10. Solution: 1. (a) Calculate the electric field of wave 2:   8 22 3.00 10 m/s 1.5 T 450 V/m Ec B  2. Because the intensity is proportional to the square of the electric field and wave 2 has the greater electric field, wave 2 has the greater intensity. 3. (b) Calculate 1 : I     2 28 1 2 2 2 10 3.00 10 m/s 8.85 10 C / Nm 52 V/m 7.2 W/m IcE 2 4. Calculate 2 : I    2 1 2 2 2 20 3.00 10 m/s 8.85 10 C / Nm 450 V/m 540 W/m Ic E 2 Insight: The intensity of wave 2 could also be calculated from the magnetic field: 8 2 26 2 7 0 3.00 10 m/s 1.5 10 T 5.4 10 W/m 41 0 T m / A c IB  2 2 .

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Chap_25_Disc[1] - 25-50 IP Electromagnetic wave 1 has a...

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