{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Chap_28_Disc[1]

# Chap_28_Disc[1] - 28-8 A microphone is located on the line...

This preview shows pages 1–3. Sign up to view the full content.

28-8 . A microphone is located on the line connecting two speakers that are 0.845 m apart and oscillating 180° out of phase. The microphone is 2.25 m from the midpoint of the two speakers. What are the lowest two frequencies that produce an interference maximum at the microphone’s location?

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
The equation that is true for all waves is f v Where in this case, v is the speed of sound. So, v f The equation that gives us what the problem is looking for is now telling us to find . So, what kind of physics is involved here? Interference! For an interference maximum, as the problem specifies, we set the path length difference equal to a whole number of wavelengths. m Now to our primary mi 2 1 2 1 2 1 ssion, which is to find . Let's let the leftmost speaker's distance to the microphone be , and the distance from the speaker to its right be . So, 0.845m 2.00m 2.4225m. 2 0.8 2.00m 45m 1.5775m. But wait! The problem also 2 specifies that the two speakers are oscillating 180 out of phase, which is or out of phase. Should we fuss and worry about whether to 2 add or subtra 1 2 2 1 ct this to or ? Well, as Wednesday said in "The Addams Family","Does it matter?" So, 2.4225m 1.5775m 0.845m . 2 2 Well, how about that? The path length difference (not counting the "out of phase"part) is the separation distance between the two speakers!
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 5

Chap_28_Disc[1] - 28-8 A microphone is located on the line...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online