Chapter 19 Discussion

Chapter 19 Discussion - 19-21. When two identical ions are...

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19-21 . When two identical ions are separated by a distance of m, the electrostatic force each exerts on the other is 10 6.2 10 9 5.4 10 N. How many electrons are missing from each ion? Picture the Problem: Two identical charged ions exert an electrostatic force on each other. Strategy: Solve Coulomb’s law (equation 19-5) to find the amount of charge on each ion, then divide the charge by the magnitude of an electron’s charge in order to find the number of electrons equivalent to that charge. Solution: 1. Solve equation 19-5 for q : 22 2 qF Fk q k r  r 2. Divide the charge by e to find N : 10 9 e 19 9 2 2 6.2 10 m 5.4 10 N 3.0 electrons 1.60 10 C 8.99 10 N m / C qrF N eek    Insight: Although the 5.4 nN force between the ions seems small, it is actually quite large at the atomic scale and would accelerate even a heavy actinium atom at a rate 92 51 6 5.4 10 N 3.77 10 kg 1.4 10 m/s ! aFm 2 19-39 . •• IP Two identical point charges in free space are connected by a string 7.6 cm long. The tension in the string is 0.21 N. (a) Find the magnitude of the charge on each of the point charges. (b) Using the information given in the problem statement, is it possible
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Chapter 19 Discussion - 19-21. When two identical ions are...

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