Axial Load 2 - IO:ldin~ ~ ". = 50(1t' .'...

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w lUOm ~_ ..... ---l. . ·A. UN ,---: -. 1> ---,--.0.- I . 0.75111 . , Ar'L a = ~Q tf\M1. VV\ "t. ~OOM~~ -:. C), 000 0'C- ~ 1. 8 ttl E -: '2.00 6- 'P~ '= 200 Clo") ~~/M '" AE: 200(10") ~ (0 ,0000 (" N\"') ~1. t::. Ie. . ::. 0,001. . 3' ~ :: "Z . . 3a\ t\'\"'" 1-/\1 . . ~---- 0.0 02 .31 ,.., +- I (BktJ) ( 0,5"",): 0;0 0 2.~ 'I W) . Ilw COOUJ ~ '2. . . k> '-4 ..., tv\ \\\e ~ co.,.,.«spo",J wi ~. ~ <+ '0\,\ "- l"'~ ~ V-O"- r;).
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w ~ J' \ e: : .. La _ 0 ..
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(j (k i) 50 CYf = 47 I-----,r{------------------ ~- L..--f-.lil#------I. ....:. ...... ,!------l. . ---I. ... __---I. ... __ ....L--_-!-- € (in. fin, (0.050 0.10 \ 0.20 €}' = 0.0.0 (l ( ) I l) r ( , - I) )Il I 2 €! = Stre -strain diagram for mild t el 0.. 5 Fig. 3-6
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~-lO. The bJ.r hilS a cross-sectiondl area 01' r\ = ~ in:. and [ = :;:,f 10") ksi. Determine the displ<lcement of its enJ A "'hen it is subjected 10 the di:ilrihuted
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Unformatted text preview: IO:ldin~ ~ &quot;. = 50(1t' .' it&gt; ill. ------~ ......---. -......-- . ...---....-A 'B ~Il----~S;--&quot; lil I) J~ 0&quot; )(-S-o ~-... bs-Lf ~1 ?&amp;) d '( A AE &quot;+'8. The a~sem[&gt;ly COn,iSl'i ,)f 1\\0 rigid bar, that are orig-inall\ hunzuntal They afe supported b\ pin, anJ U25-in-diameter A.~6 teel rods. If the \crtical load of:' kip is applied II) the buttom bar.-I B. determine the displacement at C B ~\nd -\11-[) .[ r&gt; ,. r&gt;I' c A --t---... 6 C-'s d ~ \ 0 +-cJ= 6&amp; \s AV\ +0 be&gt; c:. . ( bod B ~ E Fc.F I &lt;:-1 8 -~k-(~H:) + Fgf-(r2~ t):=:O FBe-': 2,5 k u:--. . + ~M~-::. 0 - f _ (Io~ +-'2.~t; ~ (2+ ') ~O t.l-Fc.-: 0, o ~ (~rt)(\L'\ A -0 &quot;OBLl . , t -, 11&quot;\ 1f (0. '2.5 ' ( . 2. C; C (,. s )(&quot; ~ 'fr(t,1-'t&quot;\) ('2. ,0 00 tt -,0 I ~...
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Axial Load 2 - IO:ldin~ ~ &amp;amp;quot;. = 50(1t' .'...

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