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Unformatted text preview: B). The OM is the moment that would need to be applied to the joint to bring the sum of all moments to zero. In this case +50 + UM B = 0 + UM. = 50 ft.k 5. Unlock the joint and distribute the UM's according to the Distribution Factors already calculated. 6. Carry over moment Carry over the appropriate amount of distributed end moment to the far, fixed ends of the beam, i.e., the "carry over" moment. The "carry over" moment has the same direction as the distributed moment, (remember the derivation). 7. If the structure had more than one joint that rotated, relockjoint B and proceed to the next rotating joint and unlock it., repeat steps 4 through 6. Continue to repeat steps 46 until UM's are satisfactorily small. 8. Sum the moments at each joint to complete the moment distribution. Note: do not include UM's in the sum!...
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This note was uploaded on 10/13/2011 for the course CE 377 taught by Professor Hosteng during the Fall '10 term at Iowa State.
 Fall '10
 Hosteng

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