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KIC000117

# KIC000117 - CE332 Notes Moment Distribution Example Moment...

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CE332 Notes - Moment Distribution, Part 3 Example Moment Distribution Problem Calculate all reactions and draw the V and M diagram for the following problem 0.5 k A B 0.8 kif C ! ~ J7 I J I /l D , < , < 20 ft. 20ft. 15ft. For the purposes of Moment Distribution, we can say that the above structure is equivalent to the following one: A B 0.8 kif C ~ J7 I I I /i1 35ft - k , < , < 0.5 ft.-k 20 ft. 20 ft. Step 1: Set up the Moment Distribution Table Joint A B C Mambe AB SA BC CB Stiffness, K Dislributlon Facto FEM Unbalanced Momen Distribute Carry Ove Step 2: Calculate member stiffness coefficients for each member .. 4EVl K AB := K 8A = 4*EII20 ... 2EI K oc Kc,~ 4'EV20 ~.2 EI Step 3: Calculate Distribution Factors DF AB = 0 since A is fixed DF" • K,.I (K,. +Koc) ~ .5 DF oc (1-DF" )~.5 DF ca '"' 1 since C Is a roller Slep 4: Calculate FIxed End Moments (FEM's) FEM.. ~ 0 FEMoc· 0 FEMac • -wL'112. -26.66667 FEMes- +wL 2 /12= 26.66667 FEMco = -7.5 Step 5: Calculate Unbalanced Moments (UM's). UM's are the moments needed SOthat the sum of moments at each unfIXed joint = ( -1 ) • the externally applied moment Note thallhere is an external moment at C '"'7.5 ft.-k

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KIC000117 - CE332 Notes Moment Distribution Example Moment...

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