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Unformatted text preview: $1551 $15 ANSWER3 : A-STAK: .skip (512) *( 4) BSTAK: B-set.BSTAK, %sp C-set x, %r id [%r], %r sub %sp, 4% sp st %r1, [%sp] D-id[%sp], %r2 add %sp, 4, %sp set x, %r1 st%r2, [%r1] ANSWER 4: A-Ordering from most to least terms of flexibility: 1. Dispatcher 2. Vectored linking 3. Hard addressing Since the dispatcher has more routines, it will be more flexible B-Ordering fastest to slowest terms of speed: 1-Hard addressing 2-Vectored linking 3-Dispatcher 4-Slowest Hard addressing is the only way that has to accesses memory at first....
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- Spring '11