Chapter 5 Hm. 3 Solutions

Chapter 5 Hm. 3 Solutions - Solutions to Homework #3...

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Solutions to Homework #3 Chapter 5 10. Picture the Problem : The 747 is accelerated horizontally in the direction opposite its motion in order to slow it down from its initial speed of 27.0 m/s. Strategy: Use equation 5-1 to find the acceleration from the known force and mass, then use equations 2-7 and 2-10 to find the speed and distance traveled. Solution: 1. (a) Use equation 5-1 to find a r : 2. Use equation 2-7 to find the final speed: 3. (b) Use equation 2-10 to find the distance traveled by the 747 as it slows down: ( 29 ( 29 ( 29 1 1 0 2 2 27.0 17.8 m/s 7.50 s 168 m x v v t ∆ = + ∆ = + = Insight: The landing speed of a Boeing 747-200 is 71.9 m/s (161 mi/h) and it has a specified landing roll distance of 2,121 m, requiring an average landing acceleration of −1.22 m/s 2 . 16. Picture the Problem : The force pushes on box 1 in the manner indicated by the figure at right. Strategy: The boxes must each have the same acceleration, but because they have different masses the net force on each must be different. These observations allow you to use Newton’s Second Law for each individual box to determine the magnitudes of the contact forces. First find the acceleration of all the boxes and then apply equation 5-1 to find the contact forces. Solution:
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This note was uploaded on 10/17/2011 for the course PHY 101 taught by Professor Ashkenkai during the Fall '08 term at FIU.

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Chapter 5 Hm. 3 Solutions - Solutions to Homework #3...

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