Write up - acid and base are equal the values for the...

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A. Observation Variable HCl Concentration (M) 0.104 HCl vol (mL) 30.10 HCl (L) .03010 NaOH vol (mL) 30.60 NaOH vol (L) .03060 Total moles HCl added .00313 Total moles NaOH reacted .00313 Concentration of Stockroom NaOH (M) 0.102 Mass of NaOH used (g) 0.436 Moles of NaOH 0.0109 Total volume of NaOH solution prepared (L) 0.100 Concentration of NaOH prepared (M) 0.0545 Name of partner who analyzed this sample in Part C. Chris and Variable HCl Concetration (M) 0.104 HCl vol (mL) 23.80 HCl (L) 0.0238 NaOH vol (mL) 25.20 NaOH vol (L) 0.02520 Total moles HCl added 0.00248 Total moles NaOH reacted 0.00248 Concentration of partners’ NaOH (M) 0.0984 For calculations for all tables, see yellow page #18-19 B. Evidence Looking at the chemical equation HCl (aq) + NaOH (aq) → H 2 O (l) + NaCl (aq) we realize that the moles of HCl and NaOH are equal to each other, 1 to 1. Using this information, we can calculate, after we have balanced the solution so that the moles of
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Unformatted text preview: acid and base are equal the values for the number of moles of NaOH in the base solution for both table 1 and table 3. Once we have found that we can determine the concentration of our partners NaOH solution. C. Reflection The purpose of the lab was achieved through balancing the amount of acid and base solutions by adding base to the acid solution until a clear-to-gray color was achieved and noting the specific amount of each reactant added. If we look at the balanced equation for a sulfuric acid and sodium hydroxide we see that the mole ratio of sulfuric acid and sodium hydroxide is no longer 1 to 1. With this information we can assume that the concentrations will be much different. It doesnt matter if the volume is increased because the ratio of acid to base will remain constant....
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Write up - acid and base are equal the values for the...

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