write up - For calculations see “Calculations” page C...

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A. Research Question What is the percent oxalate [by mass] in my unknown? What is the identity of my unknown? Table 1. Standardization of KMnO 4 Run #1 Run #2 Run #3 Mass of Na 2 C 2 O 4 0.204 g * * Equivalents of Na 2 C 2 O 4 0.00304 eq * * Liters of KMnO 4 0.01525 L * * Normality of KMnO 4 0.199 * * Average KMnO 4 Normality 0.199 * * Table 2. Percent Oxalate in Unknown # (3) Run #1 Run #2 Run #3 Total mass of unknown 0.202 g * * Liters of KMnO 4 13.9 L * * Equivalents of MnO 4 - .00277 eq * * Mass of the oxalate ion in the unknown 0.122 g * * % oxalate in the unknown 60.4% * * Average % oxalate in unknown 60.4% * * *=Not Enough Time to Complete Reactions
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Unformatted text preview: For calculations see “Calculations” page C. Claims The percent oxalate [by mass] in the unknown #3 is 60.4%. The identity of the unknown solution #3 is (NH 4 ) 2 C 2 O 4 ·H 2 O. D. Reflection If there were fewer significant figures in my calculations it might have changed the amount of equivalents that I had along with the total sample amount and there by affecting the percent of the oxalate Ion (by mass). This, in turn, might have “changed” the identity of my oxalate to a higher of lower concentrated compound....
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