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Exam1_Solutions(1)

# Exam1_Solutions(1) - Engr 210 Fall 2011 P Exam 1 Name Z 1(8...

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Unformatted text preview: Engr 210 Fall 2011 P Exam 1 Name: Z 1. (8 pts/ZO) (QaQ) (1) Determinethe moment offorceF 3 A — — _ _ ._ _ ﬂ about point C. Express it in a Cartesian m/ F =195 kN (3,114” 2m form. '/"‘ “ — — 4C —> a, '5)!- 1 (2 vi a (“(115 {/LA B 1 v -‘ “~"“}:;::;,:i;ii;;._.:.;;;;; (hug! \ 3*}iumowz r ”‘ | )2 "5 Cf A “ 2 D T R t “’3‘ J H g <3 I ) t A A 7“ . iv f” (35K MM “5(9'5(+IODO°[ mgogjhbl ,> -3 {\Cﬁ '7 'ﬁ __1 A «'5 g f é g; MCr " “3’4 “ 0 0*“§ i Engr 210 Fall 2011 (2) Determine the moment of force F about the axis CE. LEE 5 ~ 5:: 1 I I h? t {-23% 2% H5” 0 O —(/ ((3 (\$29 \50 1 “9619-0 KN Mn Engr 210 Fall 2011 2. (6 pts/ZO) The 30kg pipe is supported at F by a system of five cords. Determine the force in each cord for equilibrium. Draw clear free body diagrams for the solutions. (49 MOLE U g /, "—-—- j , v. Q l”c>f (7L rim 42,.“ B 153 :> I: 15C a\‘IF/1g'3w {70 (I " / 3 ‘\ - ‘ 9 ' ' l” ram? r 33? a“ s». 4-0 l "'1‘ "I - [<1 ‘ LT» ,.. 4‘ 02> W“ ~ elm—fruit} 335%? W .. 3. (6 pts/ZO) A distributed loading acts on the beam shown. (1) Determine the magnitude and location from A of the equivalent resultant force. (Figure 1 is shown for reference.) : L 5400: awry _2. 7le Cautrvfd at Th‘cWIPC-z- 5 (004155», 4+ SLM 7011)» /’l. Vm’z MSVH‘L‘” "9°N—L. 0"{ “llw reafa‘ﬁla [Mr’f r: Engr 210 Fall 2011 F2 2 090010 w‘._....._..__......,v , 7L9. 03:10—27 0( is (sealed 47’ [01M "AW/1 A {C ~. if ll}?! 5 J 000W”) 3 "W [7.7 . 'l 35'} ( loo w‘www ““““ m it: eriiadx. 5f TLo. regulfmr «703mg is (2) Determine the resultant moment about point C. Mc-: 21:1” : 600 w 3250 =’ r2600 NW ...
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Exam1_Solutions(1) - Engr 210 Fall 2011 P Exam 1 Name Z 1(8...

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