Stat 5131, Fall 1997, (Geyer) First Midterm Solutions

# Stat 5131, Fall 1997, (Geyer) First Midterm Solutions - Up...

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Up: Stat 5101 Stat 5131 Midterm 1 A stem-and-leaf plot of the grades was N = 25 Median = 83 Quartiles = 73, 95 3 : 6 4 : 4 : 5 : 2 5 : 6 : 02 6 : 55 7 : 33 7 : 8 8 : 0013 8 : 9 : 00233 9 : 57888 10 : 00 Plotting graduate students and undergraduates separately, we get grads : : undergrads ------------------ : 3 : 6 : 4 : : 4 : : 5 : 2 : 5 : : 6 : 02 : 6 : 55 : 7 : 33 : 7 : 8 0 : 8 : 013 : 8 : 33 : 9 : 002 588 : 9 : 78 0 : 10 : 0 Problem 1 There are two ways to solve this, using combinatorics or conditional probability. Combinatorial Solution. There are two-card hands. There are ways to choose an ace and ways to choose a ten, jack, queen, or king. By the ``counting principle'' there are thus hands that are blackjacks and the probability of a blackjack is

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Solution using Conditional Probability. We have to consider two cases: when the first card is an ace and when it isn't. Case 1.
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Stat 5131, Fall 1997, (Geyer) First Midterm Solutions - Up...

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