ECE3040_Homework1_Solution

ECE3040_Homework1_Solution - GEORGIA INSTITUTE OF...

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ECE 3040B: Homework #1, Solution September 9, 2011 Page 1 of 4 G EORGIA I NSTITUTE OF T ECHNOLOGY S CHOOL OF E LECTRICAL AND C OMPUTER E NGINEERING ECE 3040B: Microelectronic Circuits Fall Semester 2011, Homework #1 SOLUTIONS 1. Diamond Lattice (20 points) (a) The lattice constant of Ge at room temperature is a = 5.65 Å. Determine the number of Ge atoms per cm 3 . (b) Calculate the density of crystalline silicon at room temperature using the lattice constant a = 5.43Å, the atomic weight m = 28.09 g/mol, and the Avogadro’s number 6.023·10 23 mol -1 . Each diamond type crystal (e.g. Si and Ge) has 8 atoms per unit cell: 8 atoms at the corners each of them shared between 8 unit cells 6 atoms on the faces each shared between 2 cells 4 atoms at “inside” locations, e.g. ( ¼ , ¼ , ¼ ) and similar. 8* (1/8)+ 6*(1/2) + 4 = 8. (a) Number of Ge atoms per cm 3 = Number of atoms per unit cell divided by unit cell volume a 3 : #of Geatoms = 8 a 3 = 4.4 ! 10 22 cm " 3 (b) Density of silicon = # of atoms per cm
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This note was uploaded on 10/12/2011 for the course ECE 3040 taught by Professor Hamblen during the Fall '07 term at Georgia Institute of Technology.

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ECE3040_Homework1_Solution - GEORGIA INSTITUTE OF...

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