Ch23_p7 - flux through each face The total amount of flux is Φ net = q ε and we conclude that the flux through the square is one-sixth of that

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7. To exploit the symmetry of the situation, we imagine a closed Gaussian surface in the shape of a cube, of edge length d , with a proton of charge 19 1.6 10 C q =+ × situated at the inside center of the cube. The cube has six faces, and we expect an equal amount of
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Unformatted text preview: flux through each face. The total amount of flux is Φ net = q / ε , and we conclude that the flux through the square is one-sixth of that. Thus, Φ = q /6 0 = 3.01 × 10 –9 N ⋅ m 2 /C....
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.

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