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webwork8.8 - Nicholas Charles Miller MTH 133 KURTZ 133.007...

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Nicholas Charles Miller MTH 133 KURTZ 133.007 WeBWorK assignment number 8.8 is due : 03/08/2010 at 06:00am EST. For help on any of these problems, please consult the MTH 133 WeBWorK Forum or start a new thread with your questions. The primary purpose of WeBWorK is to let you know that you are getting the correct answer or to alert you if you are making some kind of mistake. Usually you can attempt a problem as many times as you want before the due date. However, if you are having trouble figuring out your error, you should consult the book, or ask a fellow student, one of the TA’s or your professor for help. Don’t spend a lot of time guessing – it’s not very efficient or effective. Do not give decimal answers. Instead use fractions, pi, sqrt(2), etc.. For most problems when entering numerical answers, you can if you wish enter elementary expressions such as 2 3 instead of 8, sin ( 3 * π / 2 ) instead of -1, e ( ln ( 2 )) instead of 2, etc. Here’s the list of the functions which WeBWorK understands. 1. (1 pt) Textbook section 8.8: Problem number 5 Evaluate the following integral: Z 1 - 1 dx x 10 / 11 Answer: 2. (1 pt) Textbook section 8.8: Problem number 7 Evaluate the following integral: Z 7 0 dx 49 - x 2 Answer: 3. (1 pt) Textbook section 8.8: Problem number 11 Evaluate the following integral: Z 6 5 x 2 - 5 x dx Answer: 4. (1 pt) Textbook section 8.8: Problem number 16 Evaluate the following integral: Z 5 0 x + 1 25 - x 2 dx Answer: 5. (1 pt) Textbook section 8.8: Problem number 21 Evaluate the following integral: Z 0 - xe 7 x dx Answer: 6. (1 pt) Textbook section 8.8: Problem number 23 Evaluate the following integral: Z 0 - e -| 2 x | dx Answer: 7. (1 pt) Textbook section 8.8: Problem number 32 Evaluate the following integral: Z 14 0 dx p | x - 7 | Answer: 8. (1 pt) Textbook section 8.8: Problem number 34 Evaluate the following integral: Z 0 dx ( x + 7 )( x 2 + 1 ) Answer: 9. (1 pt) Textbook section 8.8: Problem number 39 Evaluate the following integral: Z ln5 0 x - 2 e - 1 x dx Answer: 10. (1 pt) Textbook section 8.8: Problem number 46
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