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Unformatted text preview: ECE 305 Name; $019+?“ 2?
Spring 2004
Exam #1 Student No. Note: Be sure to include units where appropriate!
Note: YOU MUST SHOW YOUR WORK TO GET CREDIT! Note: Each problem is worth 8 points 1. Transient transmission lines. A battery is switched into a shortcircuited
transmission line through a series resistance, as shown below. 1:20 it 4r‘BOV
T a) Draw and label the voltage and current bounce diagrams, and use them to plot
v(0,t) and i(£,t) for OSI 36]".
£3 (480) z :20 v _ ‘70"2’0: J—  0°29,  +
P5 ' éﬁti‘ﬁ Z FL'orZbw l v “90+” 1 continued 4510,70 11%) QA r—* b) Find the steady—state current, 1'03, 1) , t ~—> oo . 2. Transmission line parameters. A highloss transmission line operating at 100
MHZ has a characteristic impedance of Z 0 : 10+ jO Q and a propagation constant of y z 5 +j10 ml. (21) Compute the phase velocity.
75: 93%) «.9 deg We ﬁt“? ‘7“ b : mama? W5 M
M (b) Compute the wavelength. NEE: o.e28m (c) Compute the loss in dB/m. dam: mega: : w 4% (d) Compute L, C, R, and G. W; .
" " ' my « ' : 50+ EGO
Kit)“ («wuamww ﬁg .. 33+ng 3
Sa; Rigﬁ/W .
L: W?” = max/o ?‘ Him
wL: 3;) ZﬁX/OOxfotb /"". Wégmji ié‘i‘“ 2 continued => 6 = 03 51% Qé i m} C: g 1.39mo’Q 57% M
Zrzxmaxfﬁb "’— W 3. Standing waves. A lossless transmission line with a characteristic resistance of
R0 = 509 is terminated by a load with impedance Z L . If the reﬂection coefﬁcient is r=0.1+jo.4, a) Finds
{7:04130‘4 : 0.492% 33 1:9: wz: 2401
[we {’0.4!Z, «3:: b) Find dm in wavelengths fﬁ~f32b “Ti432% Cir»: inﬁd): 7 3 W )a =2 ~O$SSSA
2&3 ZCQE 4f? ’3:
c) Find ZL
,, 2L~€o —7 F(ZL+%97 52L’Zo Homeﬂ Htlsxé M 1919 “
{0 2L: J t Q j z; #04104 ass304 westjéﬁg 3 continued 4. Input impedance. A 2.5 cm long section of lossless transmission line of
characteristic resistance 50 Q is operated at 1 GHz and has a phase velocity 2><108 m/s. a) Find the wavelength on the transmission line. w 2174? Zﬁx 1M09
2‘ v’ z — """' 3 5 (
qr? (5 > @— ”lﬁ; inog KM Z.L\”2II: .z
A'$”IOK 922M b) Find the input impedance when the line is terminated with a load impedance
of 100 + 150 Q. U :Ioo+'50
$€:zorr(o.ozs)= V 2" J 3?
2.“: a, W WM : “Mg”!
Katiipmgl
 ,2 iLﬁlZo ._ 50 looﬁéoﬂm ; g0 loogloo
. 0 KQ+SZL = 50mm
= 5013 so 52. M 4 continued ...
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This note was uploaded on 10/17/2011 for the course ELECTRICAL 305 taught by Professor Rothwell during the Spring '11 term at Michigan State University.
 Spring '11
 ROTHWELL
 Electromagnet

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