PHY2061 R. D. Field Department of Physics relativity_19.doc University of Florida Interaction of a Moving Charge with other Moving Charges – Case II Lab Frame (O-frame): Charge particle Q moving to the right with velocity V. Neutral wire with current I = λ+V moving to the left with λ=λ+-λ-=0, where λis the netcharge density of the wire. Particle experiences a “magnetic” force F.Particle Frame (O'-frame): Charge particle Q at rest. Wire is now positively charged with λ' =λ'+-λ'->0, and the particle experiences an electric field, E' = 2Kλ'/r' and an (repulsive) electric force F’ = 2KQλ'/r'.Calculate the force in the lab frame from knowledge of the electric force in the particle frame!Lab Frame: 000=−===−+−−++λγλ++−+===000γβλcVIParticle Frame: ++−+−−++=−′=′−′=′=′′=′0220200)(γβ)1()1
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This note was uploaded on 10/17/2011 for the course PHY 2061 taught by Professor Fry during the Spring '08 term at University of Florida.