CA_GPS_5 - ) ( = x f .] Solve the following linear...

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Rev. S08 http://faculty.valenciacc.edu/ashaw/ COLLEGE ALGEBRA NAME: ________________________________ GPS # 5 1.5 ALGEBRAIC AND GRAPHICAL SOLUTIONS OF LINEAR EQUATIONS Class Time: ____________ Date: __________ Useful Guidelines: To solve a Linear Equation in One Variable: * Eliminate the fractions: Multiply both sides by the least common denominator as needed. * Clear parentheses and combine like terms as needed. * Get all terms with the variable on one side of the equation and all numbers on the other side. * Get an equation with just the variable on one side of the equation. Zero of a Function: Any number a , for which 0 ) ( = a f , is called a zero of the function ) ( x f . If a is real, a is an x -intercept of the graph of the function. [Zeros of the function: solutions to the equation
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Unformatted text preview: ) ( = x f .] Solve the following linear equations in one variable: 1. a) 5 2 1 4 3 4 = ! ! + x x b) 2 1 7 5 7 2 4 3 + = ! x x 2. a) 25 . 01 . ) 5 ( 02 . 04 . + = ! + z z z b) 11 . 41 . 2 15 . 39 . 1 + = ! x x 3. For the function x x f 15 45 ) ( + = , find: a) ) 3 ( ! f b) The solution to the equation ) ( = x f c) The x-intercept of the graph of x x f 15 45 ) ( + = d) The zero of x x f 15 45 ) ( + = . 4. The future value of a simple interest investment is given by ) 1 ( rt P S + = . What principal P must be invested for twenty years at the simple interest rate of 5% so that the future value grows to $300,000?...
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