# cm9 - MAC 1105 Module Test 9 Name MULTIPLE CHOICE Choose...

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Unformatted text preview: MAC 1105 Module Test 9 Name___________________________________ MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Solve the equation. If necessary, round to thousandths. 1) 5e2x + 5 = 20 A) -1.807 B) -2.200 C) 3.193 D) 7.500 Use a change of base formula to evaluate the given logarithm. Approximate to three decimal places. 2) log (64.7 ) 6 A) 0. 389 B) 4.654 C) 0. 215 D) 2.327 Solve the inequality. 3) 3-x > 1 27 A) x < 1 9 B) x > 1 3 C) x > -3 Use the properties of logarithms to evaluate the expression. 4) logaa2 A) 1 B) a2 D) x < 3 C) 2logaa D) 2 Solve the problem. 5) At the end of t years, the future value of an investment of \$7000 in an account that pays 7% APR 12t compounded monthly is S = 7000 1 + 0.07 dollars. Assuming no withdrawals or additional deposits, 12 how long will it take for the investment to reach \$21,000 ? Round to three decimal places. A) 12.592 years B) 15.740 years C) 18.888 years D) 23.610 years Solve the equation. 6) 400e0. 284x = 1600 (Round to three decimal places.) A) 0. 205 B) -0. 205 C) 4.881 D) -4.881 C) ln x39 D) x39 C) 0.190 D) 1.120 Use the properties of logarithms to evaluate the expression. 7) eln x39 A) x B) ex39 Solve the equation. If necessary, round to thousandths. 8) 5(5x - 1 ) = 23 A) 0.590 B) 0.505 1 Solve. 9) Given that loga7 = 1.946 , and loga11 = 2.398 , ﬁnd loga 7 . 11 A) 0.812 B) -0.452 C) 0.452 D) 4.344 B) logt 3tu s C) logt tu3 s D) logt tu3s Rewrite as a single logarithm. 10) (logt t - logt s) + 3 logt u A) logt t u3s Solve the problem. 11) Find the amount of money in an account after 4 years if \$1800 is deposited at 5% annual interest compounded quarterly. A) \$2197.61 B) \$2187.91 C) \$2193.13 D) \$2195.80 12) Sumi Kato's savings account has a balance of \$ 1663. After 19 years, what will the amount of interest be at 5.5 % compounded annually? A) \$3159.70 B) \$2936.27 C) \$2942.27 D) \$2925.27 13) What will be the amount in an account with initial principal \$9000 if interest is compounded continuously at an annual rate of 3.25 % for 7 years? A) \$2069.63 B) \$9000.00 C) \$9297.31 D) \$11,299.12 14) \$9000 is invested at 8% compounded quarterly. In how many years will the account have grown to \$14,500 ? Round your answer to the nearest tenth of a year. A) 1.1 years B) 13.2 years C) 6.2 years D) 6 years Evaluate. kn 15) P 1 + r for P = \$14,000, n = 4, r = 11%, k = 2 k A) \$21,485.61 B) \$7485.61 C) \$20,365.51 D) \$21,252.99 Solve the problem. 16) How long would it take \$7000 to grow to \$35,000 at 6% compounded continuously? Round your answer to the nearest tenth of a year. A) 27.6 years B) 27.1 years C) 26.0 years D) 26.8 years 17) An initial investment of \$ 1260 is appreciated for 2 years in an account that earns 8% interest, compounded continuously. Find the amount of money in the account at the end of the period. A) \$4780.02 B) \$1478.62 C) \$1617.87 D) \$68,793.67 18) You have money in an account at 8% interest, compounded monthly . To the nearest year, how long will it take for your money to double? A) 7 years B) 9 years C) 12 years D) 5 years 2 19) Assume the cost of a gallon of milk is \$2.80 . With continuous compounding, ﬁnd the time it would take the cost to be 5 times as much (to the nearest tenth of a year), at an annual inﬂation rate of 6%. A) 9.9 years B) 26.8 years C) 0.1 year D) 0.0 year 20) Find the amount of money in an account after 6 years if \$2900 is deposited at 8% annual interest compounded monthly. A) \$4601.94 B) \$4664.47 C) \$4642.99 D) \$4679.16 3 ...
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