Cheat Sheet Exam #1 - 0.003=3X10-3=3E-03 position m, time...

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0.003=3X10-3=3E-03 position – m, time – s, speed – m/s acc – m/s2, force – N, mass – kg 0 is a scalar, 1 is a vector, 2, or higher - two directions and curvature of space-time displacement (position) distance=magnitude of displacement, speed=magnitude of the velocity x = x0 + v0x t y = y0 + v0y t - 1/2gt2 y = yo - 1/2gt2 0 = 2m - 1/2(9.83m/s2 )t2 t2 = 4m/9.83m/s2 = 0.407s2 t = 0.64s x = xo + 20m/s(0.64s) = xo + 12.8m 0 = 2m + (20m/s)sin45o t - 1/2(9.83m/s2)t2 0 = 2m + (20m/s)(0.707)t - (4.915m/s2)t2 4.915t2 - 14.14t - 2 = 0 t = 3.01s x = x0 + (20m/s)cos45o t x = x0 + (20m/s)(0.707)(3.01s) = x0 + 42.6m ayou = F/myou = 60N/60kg = 1N /kg = 1m/s2 afried = F/mfried = 60N/80kg = 0.75N /kg = 0.75m/s2 The mass of an object measures the amount of resistance to a change in motion or its inertia Newton’s 3 Laws If the sum of forces is zero, the object will not acc. F=ma For each force, there is an equal and opposite force Force is the rate of change of momentum. A car of mass 2180 kg slows down as the brakes are applied. Force? a
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This note was uploaded on 10/17/2011 for the course ECON 101 taught by Professor Thompson during the Spring '11 term at Michigan State University.

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Cheat Sheet Exam #1 - 0.003=3X10-3=3E-03 position m, time...

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