prbset03a_key4324

# prbset03a_key4324 - EMA 4324 Problem Set 3a 2.3 Assuming...

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EMA 4324 Problem Set 3a 2.3 Assuming standard states for all reactants and products, determine the spontaneous direction of the following reactions by calculating the cell potential (sic) : [a] Cu + 2HCl = CuCl 2 + H 2 [Cu + 2H + = Cu +2 + H 2 ] ***************************************************** Jones is really asking for a calculation of cell voltage !! [1] Cu +2 + 2e - = Cu, E o (Cu +2 /Cu) = 0.342 v; [2] 2H + + 2e - = H 2 , E o (H + /H 2 ) = 0.000 v Reaction [a] proceeds spontaneously in reverse to what is written. .. V cell = 0.342v, reaction [1] proceeds as written [reduction]; reaction [2] proceeds in reverse [oxidation] the reaction [written as a reduction reaction] with the more positive potential will proceed as the reduction reaction in a cell with the less positive [more negative] reduction reaction proceeding as an oxidation [reduction in reverse]. [b] Fe + 2HCl = FeCl 2 + H 2 ; Fe + 2H + = Fe +2 + H 2 Fe +2 + 2e - = Fe, E o (Fe +2 /Fe) = -0.440v [by insp., oxidation] 2H + + 2e

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## This note was uploaded on 10/18/2011 for the course EMA 4324 taught by Professor Staff during the Fall '09 term at University of Florida.

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prbset03a_key4324 - EMA 4324 Problem Set 3a 2.3 Assuming...

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