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Unformatted text preview: may know, is a bit low]. After 2/52 years, the dimensions will be reduced by 2*133*2/52 or 10.2 mils, 0.0102 inches [0.026 cm]. Length of cube edge is now 1.000-0.026 = 0.974 cm, V = 0.924 cm 3 , mass = 0.924*7.850 = 7.253 g 3. [5 points] According to Jones, point D represents the most accurate final coupon weight. Just for the sake of causing trouble, suppose I were to take the position that B is the better coupon weight value. Based upon your perception of what it is that you are trying to do here [cleaning-wise], how and why, convince me that I am wrong [or not]. If the initial weight loss up to point B is due to removal of insoluble corrosion products and the weight loss beyond point B is due to removal of base metal, why on earth would you assume that base metal is being removed from the start of the cleaning process when base metal is still presumably being covered by corrosion product? Number of Cleaning Cycles [Cleaning Time] Weight Loss A B C D...
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This note was uploaded on 10/18/2011 for the course EMA 4324 taught by Professor Staff during the Fall '09 term at University of Florida.
- Fall '09