CHP. 9 CIRCULAR MOTION PRACTICE SOLUTIONS1.T2.T3.T4.F5.T6.A7.C8.D9.B10. D11. C12. C13. C14. The whole pole rotates about its base as it falls at some rotational velocity. So the far end is traveling faster than the center….twice faster. Since the center hits at 10 m/s, the far end hits at 20 m/s.15.This problem is the same as problem 13, above. The answer is given at the beginning of the last paragraph on page 132 of the text.Simulated gravity’s effect rests on the fictitious centrifugal force which is an “outward” feel from the centripetal force on the rotating wall on which we’re “standing”. Now this force is directly proportional as : Fc ~ (m v2 )/r , but v is directly proportional as v ~ r ω. So if we substitute in for v2 in the expression for Fc, we get: Fc ~ (m v2 )/r ~ m (r ω)2 /r ~ m r2 ω2/r ~ m r ω2 The acceleration (simulated gravity) felt by a person of mass m is then directly proportional as: a = Fc/m ~ r ω2 so if you go from 200 meters from the axis of rotation to 100 meters from that axis, the aceleration you feel will halve. While
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