{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

exam4_page1 - and by rotation about its CG Let’s list the...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Exam 4 SAR Physics AM Kolchin 1. Linear speed ( v ) is directly proportional to the rota- tional speed ( ω ) and the distance ( r ) of the point from the axis of rotation: v . 2. Centripetal Force on an object: F c = mv 2 r 3. Torque ( Γ): Γ = F d . The distance ( d ), is from the point at which the force is applied to the axis about which the torque is exerted. 4. Rotational Inertia (I): A small object of mass m , a dis- tance r from its axis of rotation, has a rotational inertia: I = mr 2 . 5. Rotational Acceleration ( α ): defined as rate of change of rotational speed per unit time: α = Δ ω/ Δ t . 6. Newton’s Second Law for Rotational Motion : Γ = . 7. Angular Momentum ( L ): L = . 8. Kinetic Energy : Total K.E. = Translational K.E. + Rotational K.E. K.E. total = 1 2 Mv 2 + 1 2 2 1
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
9. Translational and Rotational Analogs : We’ve said that an object’s motion can be described by translation of its CG
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: and by rotation about its CG. Let’s list the translational and rotational quantities and laws that are counterparts of each other: Translational Rotational velocity ( v ) rotational velocity ( ω ) ( m/s ) (rpm, 1 /s ) acceleration ( a ) rotational acceleration ( α ) ( m/s 2 ) (rpm/ s , 1 /s 2 ) mass ( m ) rotational inertia ( I ) ( kg ) ( kg * m 2 ) Force ( F ) Torque ( Γ ) ( N ) ( N * m ) ( note: not joules; joules are reserved for energy only .) Momentum ( p ) Angular Momentum ( L ) kg * m/s kg * m 2 /s K.E. (trans) = 1 2 Mv 2 K.E. (rot) = 1 2 Iα 2 (joules) ( J ) (joules) ( J ) Newton’s Second Law F = m a Γ = Iα p is conserved L is conserved 2...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern