HWK16s_11G - work done on the object is: W = F × d = 10 N...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
HWK 16 ( 11 th Grade) SOLUTIONS A M Kolchin/ SAR Physics Read pages 103 - 107. Do (on page 119): 1, 3, 4, 5, 7 1. Work is force × distance. When we do work on an object, we change its kinetic energy, potential energy, or both its kinetic and potential energies. 3. Lifting a 10 kg. load a vertical distance of 2 m requires an amount of work: W = m × g × h = 10 kg. × 10 m/s 2 × 2 m = 200 J. and lifting a 5 kg. load a vertical distance of 4 m requires an amount of work: W = m × g × h = 5 kg. × 10 m/s 2 × 4 m = 200 J. so both jobs require the same amount of work. 4. When a force of 10 N pushes an object a distance of 10 m the
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: work done on the object is: W = F × d = 10 N × 10 m = 100 J . 5. The Power required to do 100 J of work on an object in .5 s is: P = W/ Δ t = 100 J/. 5 s = 200 W. To do this same amount of work in 1 s requires a power of: P = W/ Δ t = 100 J/ 1 s = 100 W. 7. If you do 100 J of work in lifting a bucket, you will increase its potential energy by 100 J. If you lift the bucket twice as high, you will double the original increase in P.E., so the bucket will have 200 J of gravitational P.E. 1...
View Full Document

This note was uploaded on 10/19/2011 for the course PHY 2020 taught by Professor Staff during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online