HWK16s_11G - work done on the object is W = F × d = 10 N...

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HWK 16 ( 11 th Grade) SOLUTIONS A M Kolchin/ SAR Physics Read pages 103 - 107. Do (on page 119): 1, 3, 4, 5, 7 1. Work is force × distance. When we do work on an object, we change its kinetic energy, potential energy, or both its kinetic and potential energies. 3. Lifting a 10 kg. load a vertical distance of 2 m requires an amount of work: W = m × g × h = 10 kg. × 10 m/s 2 × 2 m = 200 J. and lifting a 5 kg. load a vertical distance of 4 m requires an amount of work: W = m × g × h = 5 kg. × 10 m/s 2 × 4 m = 200 J. so both jobs require the same amount of work. 4. When a force of 10 N pushes an object a distance of 10 m the
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Unformatted text preview: work done on the object is: W = F × d = 10 N × 10 m = 100 J . 5. The Power required to do 100 J of work on an object in .5 s is: P = W/ Δ t = 100 J/. 5 s = 200 W. To do this same amount of work in 1 s requires a power of: P = W/ Δ t = 100 J/ 1 s = 100 W. 7. If you do 100 J of work in lifting a bucket, you will increase its potential energy by 100 J. If you lift the bucket twice as high, you will double the original increase in P.E., so the bucket will have 200 J of gravitational P.E. 1...
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