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Unformatted text preview: V R 2 = IR 2 = (1 A )(40Ω) = 40 V 6. What is the power used by R 2 ? P R 2 = V R 2 I = (40 V )(1 A ) = 40 W 7. What is the voltage drop V R 3 across R 3 ? (Apply Ohm’s Law between points c and d.) V R 3 = IR 3 = (1 A )(60Ω) = 60 V 8. What is the power used by R 3 ? P R 3 = V R 3 I = (60 V )(1 A ) = 60 W 9. Add the voltage drops across R 1 and R 2 and R 3 . V R 1 + V R 2 + V R 3 = 20 V + 40 V + 60 V = 120 V 2 10. What is the total power drawn from the voltage source? P T = P R 1 + P R 2 + P R 3 = 20 W + 40 W + 60 W = 120 W . or P T = V T I = (120 V )(1 A ) = 120 W 3...
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This note was uploaded on 10/19/2011 for the course PHY 2020 taught by Professor Staff during the Spring '08 term at University of Florida.
 Spring '08
 Staff
 Physics, Resistance, Work

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