hwk_chp11 - HWK PGS:378-379 29 30 31 34 35 40 43 48(a b c...

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29. From the balanced equation, we can see that for every two moles of Al that gets fully reacted, we will get three moles of Cu . 30. From the balanced equation, we can see that for every three moles of Cl 2 that gets fully reacted, we will get two moles of FeCl 3 . So from six moles of Cl 2 , we’ll get four moles of FeCl 3 . 31. According to the equation, two moles of H 2 O react completely with 2 moles of Na , so 12 moles of H 2 O will react completely with 12 moles of Na . 34. We see that 2 moles of NaI will produce 1 mole of PbI 2 , so 6 moles of NaI will produce 3 moles of PbI 2 . One mole of PbI 2 contains 1 mole of Pb atoms and 2 moles of I atoms and has a mass: M 1 mol = 207 .g/mol * 1 mol + 2 * 127 g/mol * 1 mol = 461 g . So 3 moles has a mass: M 3 mol = 3 * M 1 mol = 1380 g . 35. We have M Li = 87 .g of Li or N Li = 87 .g * 1 mol/ 6 . 9 g = 12 . 6 mol of Li . Since 4 moles of Li reacts with 1 mole of O 2 molecules, 12.6 moles of
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hwk_chp11 - HWK PGS:378-379 29 30 31 34 35 40 43 48(a b c...

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