380F11SolnPS1

380F11SolnPS1 - 01:447:380 Fall 2011 SOLUTIONS FOR PROBLEM...

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01:447:380 Fall 2011 SOLUTIONS FOR PROBLEM SET 1 Additional Problems 1. Here are the arrangements of chromosomes during metaphase I. There are two possible arrangements because of the Principle of Independent Assortment. Let | = metaphase plate. C 1M | C 1P C 1M | C 1P C 2M | C 2P C 2P | C 2M 2. A. Piebald spotting is a dominant trait. Both parents are affected, but they have a child with normal pigment. Therefore, the parents must be heterozygous so that each can contribute a normal allele to the normally pigmented child. The dominant trait is the trait expressed in a heterozygous individual. B. We can let P = piebald spotting and p = normal. Then both parents would be Pp . 3. A. 50% B. Man must be heterozygous; Let D = dimple and d = no dimple. Man’s genotype is Dd . C. We cannot be certain of the man’s genotype. If he was heterozygous, there would be a 50% chance of the couple having a non-dimpled child. Based on the fact that all 8 children are dimpled, it is likely that the man is homozygous for the dimple allele ( DD using the nomenclature above). However, we cannot be certain of this because each child is an independent event, and it is possible for Dd x dd to have 8 children that are
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This note was uploaded on 10/18/2011 for the course GEN 380 taught by Professor Glodowski during the Spring '11 term at Rutgers.

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380F11SolnPS1 - 01:447:380 Fall 2011 SOLUTIONS FOR PROBLEM...

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