quiz1 - n you don’t need the previous line to see...

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Ok check it out. I think this is right: d 1 ( e j i )( e k ,e l ) = e k e j i ( e l ) + e j i ( e k ) e l + e j i ( e k e l ) (using “Einstein notation”) = e k δ il e j + δ ik e j e l + e j i ( T m kl e m ) = δ il T n kj e n + δ ik T n jl e n + T i kl e j (without Einstein) = Σ n 6 = j ( δ il T n kj + δ ik T n jl ) e n + ( δ il T j kj + δ ik T j jl + T i kl ) e j (with Einstein–summing over
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Unformatted text preview: n . you don’t need the previous line to see this. .the previous previous will do) = ( δ il T n kj + δ ik T n jl + δ nj T i kl ) e n 1...
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This note was uploaded on 10/18/2011 for the course S 2010D taught by Professor Peters during the Spring '10 term at Columbia.

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