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Unformatted text preview: π + = = = ∫ Average current is d V R , so 2 cos m d V I R = Addition of Freewheeling Diode 4 5 Average load voltage: ( 29 1 sin 1 cos m d m V V V d π α ϑ ϑ = = + ∫ Average load current: ( 29 1 cos m d V I R = + Average current in the freewheeling diode: The current in the FWD is the same as the load current in the interval from 0 to and for a similar interval in the second halfcycle. 1 FWD d d avg I I d I ϑ = = ∫ ÷ 6...
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This note was uploaded on 10/05/2011 for the course EECS 101 taught by Professor Hero during the Spring '11 term at National Taipei University.
 Spring '11
 Hero
 Volt

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