L2_4 - Overlap commutation ab v ac v bc v ba v ca v cb v L...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Overlap commutation ab v ac v bc v ba v ca v cb v L L L L L L L R 1 TH 2 TH 1 i 2 i Equivalent circuit 1 TH d ab di v v X d ϑ =- 2 TH d cb di v v X d ϑ =- 1 2 TH TH d i i I + = a V b V c V ab V bc V ca V cb V ( 29 3 ( ) sin ab ml v V π ϑ ϑ = + ( 29 2 3 ( ) sin cb ml v V π ϑ ϑ = + 1 2 2 TH TH d ab cb di di v v v X d d ϑ ϑ = +- + ÷ 18 1 2 TH TH di di d d ϑ ϑ + = 2 d ab cb v v v = + ( 29 1 2 d ab cb v v v = + ( 29 ( 29 ( 29 2 3 3 1 1 3 sin sin cos 2 2 2 d ab cb ml ml ml v v v V V V π π ϑ ϑ ϑ = + = + + + = 1 TH d ab di v v X d ϑ =- 2 TH d cb di v v X d ϑ =- ( 29 ( 29 1 2 3 3 1 1 ( ) sin sin 2 2 sin 2 TH ab cb ml ml ml di v v V V d X X V X π π ϑ ϑ ϑ ϑ =- = +- + = = 1 ( ) TH i ϑ can be calculated as 1 ( ) sin 2 ml TH V i d A X ϑ ϑ ϑ = + ∫ 1 ( ) cos( ) 2 ml TH V i A X ϑ ϑ = - + Assuming ϑ α = at the beginning of commutation, where 1 TH i = , the constant A can be evaluated as cos 2 ml V A X α = and [ ] 1 cos...
View Full Document

This note was uploaded on 10/05/2011 for the course EECS 101 taught by Professor Hero during the Spring '11 term at National Taipei University.

Page1 / 4

L2_4 - Overlap commutation ab v ac v bc v ba v ca v cb v L...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online