# L2_4 - Overlap commutation ab v ac v bc v ba v ca v cb v L...

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Unformatted text preview: Overlap commutation ab v ac v bc v ba v ca v cb v L L L L L L L R 1 TH 2 TH 1 i 2 i Equivalent circuit 1 TH d ab di v v X d ϑ =- 2 TH d cb di v v X d ϑ =- 1 2 TH TH d i i I + = a V b V c V ab V bc V ca V cb V ( 29 3 ( ) sin ab ml v V π ϑ ϑ = + ( 29 2 3 ( ) sin cb ml v V π ϑ ϑ = + 1 2 2 TH TH d ab cb di di v v v X d d ϑ ϑ = +- + ÷ 18 1 2 TH TH di di d d ϑ ϑ + = 2 d ab cb v v v = + ( 29 1 2 d ab cb v v v = + ( 29 ( 29 ( 29 2 3 3 1 1 3 sin sin cos 2 2 2 d ab cb ml ml ml v v v V V V π π ϑ ϑ ϑ = + = + + + = 1 TH d ab di v v X d ϑ =- 2 TH d cb di v v X d ϑ =- ( 29 ( 29 1 2 3 3 1 1 ( ) sin sin 2 2 sin 2 TH ab cb ml ml ml di v v V V d X X V X π π ϑ ϑ ϑ ϑ =- = +- + = = 1 ( ) TH i ϑ can be calculated as 1 ( ) sin 2 ml TH V i d A X ϑ ϑ ϑ = + ∫ 1 ( ) cos( ) 2 ml TH V i A X ϑ ϑ = - + Assuming ϑ α = at the beginning of commutation, where 1 TH i = , the constant A can be evaluated as cos 2 ml V A X α = and [ ] 1 cos...
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## This note was uploaded on 10/05/2011 for the course EECS 101 taught by Professor Hero during the Spring '11 term at National Taipei University.

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L2_4 - Overlap commutation ab v ac v bc v ba v ca v cb v L...

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