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Unformatted text preview: Physics 325 Lecture 18 Here is what we know so far: 1) Two clocks that are synchronized in their rest frame appear non-synchronized when viewed from a frame that is in relative motion to the clocks. 2) A moving clock runs slow compared to a clock at rest. 3) A moving object appears to be shorter when measured along the direction of motion than the same object at rest. We re-visit the simultaneity problem: s viewed from a frame S that is co-moving with the t time the flash arrives at clock A At time the flash arrives at clock B. A A A B v G S S t = A A A B v G S S t = At t = a flash of light goes off that i two clocks A and B , and from S from which the frame S is moving with velocity v G . A A A B v G S A A A B v G S A A A B v G S S A t t = A t t = A A A A B v G S A A A B v G S A A A B v G S S B t t = B t t = For A t t = , an observer in frame S sees ( ) A A A A ct vt vt t c v = = = + A A A For B t t = we have in S ( ) B B B ct vt vt t c v B = + = + = A A A rval between events t A and t B of So an observer in S measures a time inte 2 1 1 2 B A v t t t c v c v c = = = + A A If at clock A was set to zero, at A t t = B t t = clock A shows, according to an observer in e tim S , th e t t = because a moving clock runs slow. So our...
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This note was uploaded on 10/06/2011 for the course PHYS 225 taught by Professor Makins during the Spring '10 term at University of Illinois, Urbana Champaign.
- Spring '10