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ProblemSet3_Solutions - Distributed V Due Reading...

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Unformatted text preview: Distributed: V Due: Reading Assignment: Hibbeler Sections 10.6 (+examples 10.10&10.11), 4.3, 4.4, 4.5, 4.6, 8.1 Solve all the following problems assuming that the material is linear, isotropic, elastic Problem 1: Problem 2: Problem 3: Problem 4: Problem 5: Problem 6: MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Mechanical Engineering 2.001—Mechanics and Materials I Spring, 2006 Problem Set 3 Tuesday, February 27, 2006 Monday, March 6, 2006 Hibbeler 3-16 (E31221 =200 GPa) Hibbeler 3-26 Hibbeler 3-33 Hibbeler 3-37 (EA,=7O GPa) Hibbeler 4-10 Hibbeler 4-27 (The plate has properties E, v) {'UAA‘. How Wanda JAM WM sfit‘rckrs -— 6‘ w New ' Com 3"“ AW ‘5‘” (‘3) 6;; t (D Find Bra)“; QR=D= Rf — Easing “PP iFu =0: R; .38 mag €(szc =0 = A9. sing (O~¥E‘) - 2H0 (0 Fm '5“ PL...— s‘mg (cw-w} m wUfQ .529 ‘ 6 ___ 4FAB A =7 °~ ww- ‘lanrAZ d Vfld‘fi 0" 3““49 E E2 =5 £=é (-n -—> (A3 {\‘é E13 Lo AE. » (m “(43 = WoLo A‘a («HQ -‘ ‘m 3‘5 EW’Q = 1013MB“ Tau re‘xafl‘x oWQn C (9 VP: QLa Lo :. curb _ 0:59 a = 7g‘0304‘3m = DAWN ”9+ {\ " \ m NE 5mg (03 9 = (\x zou‘xc \\‘Z\°\ '2'?) \‘WFC o.oo§o?;v«\7'C’L°O NJ“ PA Cos Ed’sM‘JB" =_/ Cu sfgwmv 3 to 1-1 ' C O- 01%‘\w~ C5) 7&4;in ' 67mm .H Foe/«3., (Mash?) . ,enazééaaga 4 Wm 404m,4’/ r Zflxzo- 7> N:P K 17: (/Fx/Ofig),2 —3 Zoo” /0 m ,c 500% 29 ?'X (07,”, saw; M’ém 0, 00 322mm __._. , H .,.,_.,._.u ...,. Muir}- um wmmmu ....,._.,.._,_.... m u; fl? :1; u; w. ,._..._.M H: 4 .HWA. Q mewm ”Wmmm Mwm. :_ 7 :_ um. w“ ”MM : W W V \D shave = 32mm &?\“3 = 30mm E = SMV'R u - oAS' 'Fx‘ncx‘» 03 P sud/x Wefi- 'PW‘) con-Hdrs rig-"(ix Wm“ 53 ‘ve\cm3a\\'ol\ ‘ 04‘ @ua VP CMQAM S—hwn \m {Wamgveru véx‘xivu’n‘orxv SWIM *MOA’ P\ua_ ED“C\W€S WM 2-3e_ , Sir-ems: 5—4.. 3 _. 0.0b(p(,". dflua’ 3O -‘(SHW PQCENM ~ao~A D\ «5 ( 30‘4“» i ‘ garb-0 ' Lo {3 = Evy-39,0 Lo = 1% L» dawn} = '(31‘ww-50'MA' 50MM=- o-4'S (EDMQ WWWWWwWW~+—__.L—_+mw~nw,w W WM “WM,“ M, ‘-_._ mm; A ., W Mm», M «was... WflmeJmWQEéW‘WHMW mmmmm mem.wwwmmmmfifizé‘m/flts 1.20/4 ‘76 ahmmzm, {jig/MM {flame/m” Eggjmw' w “~— 6 «WM... ~wmm.—.~w..,mm»m, mum-m 7, 3.-....mx. _.-._.vW..0M.-WNW >FTP“???21"?“113E‘“r”‘:fi"*‘d*’x‘1’.z‘fi'gr‘ :«s‘ffi'z :3 1W='"‘¢',:glg’:‘ftgr ‘32}ng ~: 3.3333,; . , ,3,“ may, "5 '1! 3 3‘ 33”“. mm» MAW M 4m + we raid 411% 6144-1..740'5: r -— 4 #4 x Z v.“ «n... “WMM‘R ”.4...“ :4 , u 1‘! ¢a If; 4 Wm ._ m- - _. h. a. ». 223;;9747; *NWMW-W 7 .. . WVo’JMW.WW ”my..,.,......V,,..._'_.q..,.l,,_.‘..._.~_,,.,,_..,..,A_V r .4, J, F'néx \ {N -.: Aispmcefinad @ ehd CD TWA 9053 e— 6- : —-—> m» (~— 4-— ‘r"? 7: {RED = pm ‘ [mum “FED I T e PH") =§ wm‘MI ”j 500 1‘30“): d 6 PBS : 500(34‘ 143] a @1291ka 63;; VOVLQ ISMSS ka‘ona‘kx‘p ’60» (V\ = ptiq ' A ® Urea: / awam ”Mamba“? V¢'\“\O“W“€ Eu (1» 7- €a(‘£3 E ( @ D\$Q\AW {$T'M‘xw 5&3 =1 Ea (3;) oh: @3 “-3 GD duhfi : 69(1) . d1 5 (z) .5 a) duh) = PC23 oh: AE» L L {dul‘d = $33 an 0 AE 4AE ‘7 Z ¢ — @529 , 1c 4(5in§)(’>’5‘mob)m [=37 (43“) 5 g = 3572*“3‘9 (gggggss) ./ l L “is: “(0);0 -m—Mamh ...
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