ProblemSet7_Solutions

ProblemSet7_Solutions - MASSACHUSETTS INSTITUTE OF...

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Unformatted text preview: MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Mechanical Engineering 2.001-Mechanics and Materials I Spring, 2006 Problem Set 7 Distributed: Wednesday, April 12, 2006 Due: Wednesday, April 19, 2006 Reading Assignment: Hibbeler: sections 6.5, 6.6, 7.1, 7.2, 7.3 Problem 1: Draw accurate Sketches (with values!) for the shear force and bending moment diagrams for the loaded beams depicted below (yes, you have seen some of these in homework 1). For angled beams divide in sections, as discussed in class. Problem 2: Hibbeler 6-7 Problem 3: Hibbeler 6-11 Problem 4: Hibbeler 6-15 Problem 5: Hibbeler 6—36 Problem 6: Hibbeler 6—37 . -f lit“ LN I (it) (iv) 9‘; n can venHon MEI“ GHVCKA . x A PSET 1*— ‘1 “Wm. M 2 , o o A. ‘1 “’4'” L’“ POSITIVE Sum FED Caravan-n (NJ W v v Sign canvenHm ‘M/W KM Mij—w V” £5619va \f EWh'buum: ZFxS‘O Eff-"0 Zcho £34+2a6—P*0},b=0 ZWJW - F22 —(?b)/4+§) + A may “W’s (wwar ~+ Ethchrxm O \“Dmuk bEmzung I x) Q9 r 5.0-?" be “has Dos sum (0 H Al:— («KEN—“5’ V 5’2 n can renHon fable?) 1.; (VOL) V, Eigi/fbfium ZFXzo KXA'I’PZO Ext: 'P A- P ZFyfio ZKMe)a‘° EyygL " PH=0 E = PH { V L 4: 13+: 23/ 3L 3). 3L x I 1% VW 2(Me>y"° MU‘)+§&X=0 3 g 1‘ MW éuZJHbrfi/m H I ;5 A 3‘13 ZFyto -V(x)— -P—-zo Iva)“ Bi 3L “1 x Zlgfibu‘mm maC’Fp (TB/:0 Wow—giro ma) 1% WW) a Z'@.’£)X:o _/M(,(Z) _+_ fisz o 1 3L 5),. Z "~‘ - Fibo '3’? — VCK3>+ R9599 = 0 1/09): 105/999 23%. - 3L. X4 2014; =0 M033) - P5m9/x3-L) WL) WmsQIOFU - Wsmg 7.0.7.]; ~\.2w + QJFLW + Q“ (3Q +M’ZW “WW R‘s : (M2) :- NM 2 BO- ' \o 349 3 (23° -.-. \owd RjA : 20%” I H H , v; swam. {FED d\ E , 3; 0.1 w (2;, QVBITO T: > R53! :1 WCogS ' 5 C RSI = W a ‘93 2:1. ,0 — b UM; -_ BOHJJUM 2:3,) {3%, = UUSMQ - (239 $ 31*“ : @okkl {03;} : \Bkk) flM—Jfi O = M‘ + chmGCo‘Cfi Mc = - wc a3::<c>m = ' “:30 km(o ¢%X0.R\ 1%,-w. a/M- .. 5") 77—1/ [Ix W/Ib'fium ZFya-o A-leA/eft—A/cc 97*: 15/4/1/ 20%)”: 0 = M” + 40W“: 2m + (fng 5m +/¢S¢/1 ‘M‘-= 2 m ! 3 m ' (5:) 29’“ wow ~W5» Give» P !P ?im.\. ‘. CL. Sud/w ’rVCJC “WWW: , ~ MOMQU‘; ‘\ 3 M\‘(\\‘ M\ bea\ A bb'l'H (3 P P 13 233:0 =e;+2~f-;p ‘ ‘ a " \“L 93 . as my; aim. 42.3 Mg /.5 arm 4% 5 I “(TV W? W — j C X) _ _, ‘ «LL ‘ x 4' g; 3 3 K 2 up 2%)“) -m(x)+4¢833x 4.5%: - D ‘ _ MM): 4.853x —/o§_7£_ l r . I ...,W.W~ “mmmww”..mfimm ‘ f m {(sz = ‘W x 1233mm — QUAD?) 239: = MA Q (\4 4h \SDCD \bfiufl +{fl'xtc3’\£{\‘\(3¥‘ W‘mw14v~4w-u-mzomfi \1C+ \1£+ = ) A (7—) —3 C?“ R; = Q—Rg": qmflb ‘ was Us. Mm: (nova ‘“ 5y \2C+ \ ‘ t - 1,0500 “90+ U, A — ‘- 1‘: a. t; —-—-\Soo \ULS was t O‘qz Q)“ AV -‘-w(13 y Vb?)- CUQS'IQM A r “E: f3 - R5 5" ;;_.........,..,::::fi: '3 “c 1—“3L “'4 _ (0 £F=O=R*+R°_WL “3 3 U _ "i ‘2" am]? MC * a}: (32L? -' RbAL Q\ ~2‘L’De' "; 7. — - w (o.”22>$W3LE + Zw L (C) 21.); ,2— 3'1 ox "L — - \u L .. 7 .C- wL. 0.0tfl‘3 l. 4. O €3-39 Maw = o.o\0\wCL \I ‘ " V“ ...
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ProblemSet7_Solutions - MASSACHUSETTS INSTITUTE OF...

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