This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: MASSACHUSETTS INSTITUTE OF TECHNOLOGY DEPARTMENT OF MECHANICAL ENGINEERING 2.370/2.37 Molecular Mechanics Fall 2007 PROBLEM SET 1 Solution Assignments from Molecular Driving Forces , Dill & Bromberg. 1. Chapter 1, Problem 1 a) The probability that you have at least one acceptance is equal to 1 minus the probability that you get rejected everywhere. Thus P (at least one acceptance) = 1- P (all three rejecting) = 1- (1- . 1) (1- . 3) (1- . 5) = 0 . 685 Note that (1- . 1) is the probability that one is rejected by UCSF, (1- . 3) is the probability of rejection by DSM and (1- . 5) is the probability that one is rejected by Harvard. b) The probability of being accepted at both Harvard and Duluth is P ( DSM ) P ( H ) = 0 . 3 . 5 = 0 . 15 As is typical for probability questions, there are many ways to obtain the correct answer (the methods given above are probably the easiest). For example, we could have enumerated all of the 2 3 = 8 possible combinations of being accepted/rejected by...
View Full Document
This note was uploaded on 10/06/2011 for the course MECHANICAL 2.37 taught by Professor Hadjiconstantinou during the Fall '07 term at MIT.
- Fall '07
- Mechanical Engineering