cs313-2006-t2-problemset7-solution

cs313-2006-t2-problemset7-solution - CPSC 313 06W Term 2...

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Unformatted text preview: CPSC 313 06W Term 2 Problem Set #7 - Solution 1. (a) 1 185 ps = 5 . 41 × 10 9 cycles per second or 5.41 GHz (b) 5.41 Gops (instructions per second) (c) 5 * 185 = 925 ps per instruction (d) i. 1 600 ps = 1 . 66 × 10 9 cycles per second or 1.66 GHz ii. 1.66 Gops (instructions per second) iii. 600ps per instruction (e) I would split the largest stage (175 ps) which would allow the clock period to decrease from 185ps to 160ps. (f) I would split the largest 2 stages (175 ps and 150ps) which would allow the clock period to decrease from 185ps to 110ps. (g) i. 1 110 ps = 9 . 09 × 10 9 cycles per second or 9.09 GHz ii. 9.09 Gops (instructions per second) iii. 7 * 110ps = 770ps per instruction 2. (a) Causal %ebx (b) Causal %ebx (c) Causal %ebx (d) Anti %ecx (e) Output (%eax) (f) Control (g) Control (h) Control 3. While solving this question, it is imperative to understand that causal dependecies and control depen- dencies cannot be resolved by rewriting the code. The only two dependencies that can be resolved aredencies cannot be resolved by rewriting the code....
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This note was uploaded on 10/09/2011 for the course CPSC 344 taught by Professor Karen during the Fall '10 term at UBC.

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cs313-2006-t2-problemset7-solution - CPSC 313 06W Term 2...

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