Unformatted text preview: h (81) = − 35 cos
(81) + 37
53
h (81) = 71.4
h (t ) = − 35 cos Or use the simpler method of 2nd Trace Value x = 81 2π
t + 37
53 d) 7
0 In your TI83, graph the equation and also the line y = 51. The first
intersection point will give the time the height first reaches 51 m. Height (m) 6
0
5
0
4
0
3
0
2
0
1
0
2
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0 51 m is first reached at 16.7 s
Time (s)
 2.
a) The diameter is 28 m, so the radius is 14.
The period is 15 seconds. avalue: The amplitude is 14
bvalue: b= 2π 2π
=
P 15 cvalue: None for cosine
dvalue: The highest point is 30 m off the ground and the c) radius is 14 m, so the midline will be at 16 m. 2π
t + 16
15
*Use a positive since the rider gets on at the top, and
therefore the cosine graph is upright.
h(t ) = 14 cos Height (m) b) 3
0
2
5 The rider is at a height of 20 m at the
following times:
3.06 s
11.9 s
18.1 s
26.9 s 2
0...
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This note was uploaded on 02/09/2011 for the course 168 comm 168 taught by Professor Kiscabean during the Winter '10 term at UCLA.
 Winter '10
 KISCABEAN

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