This preview shows page 1. Sign up to view the full content.
Unformatted text preview: on an industrial flywheel experiences a motion described by the formula: h(t) = 13cos 2π t +15 0.7 a) What is the maximum height of the point? b) At what time is the maximum height reached? c) What is the minimum height of the point? d) At what time is the minimum height reached? e) How long, within one cycle, is the point lower than 6 m above the ground? f) What is the height of the point if the wheel turns for 2 hours and 20 minutes? Pre – Calculus Math 40S: Explained!
www.math40s.com 78 Trigonometry Lesson 8:
Part I – Ferris Wheel ANSWERS
a) a-value: The amplitude is 35 (upside down since the
rider gets on at the bottom, so use a negative in the equation b-value: b = 2π = 2π
53 c) ) c-value: None for cosine
d-value: The lowest point is 2 m off
the ground and the radius is 35 m, so the
midline will be at 37 m. h(t ) = −35 cos b) To find the height at 81 seconds, plug the time into the equation. 2π
t + 37
View Full Document
This note was uploaded on 02/09/2011 for the course 168 comm 168 taught by Professor Kiscabean during the Winter '10 term at UCLA.
- Winter '10