Experiment 18 Questions - Lab 18 Discussion: The product of...

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Lab 18 Discussion: The product of this reaction is biphenyl plus the para additions of tert-butyl groups. The H NMR supports this because it displays three unique hydrogen signals. Two are located on the benzene rings and display shifts in the range of 7 to 8. They couple to each other and produce two doublets. There is also a large hydrogen signal that is shielded between 1 and 2. It is the 18 equivalent hydrogens on the tert-butyl group that adds in the para position to the biphenyl. This spectrum was helpful because if the butyl group had added ortho instead or para, more splitting would have been evident in the aromatic range between 7 and 8. Since there are only two doublets, the t-butyl group must exist in the para position. The other 5 possible isomers of this product would have exhibited more coupling in the spectrum. The Carbon 13 NMR spectrum was also a useful tool to help determine the molecular structure. The two signals at 140 ppm correspond to the carbon that bond at the para position
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Experiment 18 Questions - Lab 18 Discussion: The product of...

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