887 Chapter 22 Electromagnetic waves CHAPTER 22 PROBLEMS 5,  5.Strategy and SolutionAt a point due south of the transmitter, the EM waves are traveling due south. The electric field at this point is oriented vertically, like the antenna. The magnetic field is perpendicular to both the electric field and the direction the EM waves travel, so the magnetic field must be oriented east-west. 6.Strategy and SolutionAt a point due north of the transmitter, the EM waves are traveling due north. The electric field at this point is oriented vertically, like the antenna. A receiver should be oriented the same as the transmitter, so the orientation of the receiver should be vertical. CHAPTER 22 PROBLEMS: , , 17, 19, 27, 32 12. StrategyThe frequency, wavelength, and speed of EM radiation are related by.fcλ=SolutionCompute the wavelength of the radio waves.863.0010 m s3.3 m90.910Hzcfλ×===×15. StrategyThe speed of light in matter is given by,vc n=where nis the index of refraction. SolutionCompute the index of refraction of topaz.883.0010 m s1.621.8510 m scnv×===×17. StrategyThe time of travel is equal to the distance traveled divided by the rate of travel. SolutionCompute the time it takes for light to travel 50.0 cm. 29850.010m1.6710s1.67 ns3.0010 m sdtc−−×Δ ===×=×19. (a) StrategyThe wavelength is shorter in matter than it is in vacuum. Use Eq. (22-5). SolutionCompute the wavelength of light inside the glass.vg692 nm455 nm1.52nλλ===(b)StrategyThe frequency in glass is the same as the frequency in air. Use.cfλ=SolutionCompute the frequency of light inside the glass. 814ga9a3.0010 m s4.3410Hz69210mcffλ−×====××27. StrategyThe electric and magnetic fields oscillate with the same frequency, and their amplitudes are proportional to each other. Use Eq. (22-6).
has intentionally blurred sections.
Sign up to view the full version.