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Unit 14 Solutions

Unit 14 Solutions - Chapter 22 Electromagnetic waves...

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887 Chapter 22 Electromagnetic waves CHAPTER 22 PROBLEMS 5, [6] 5. Strategy and Solution At a point due south of the transmitter, the EM waves are traveling due south. The electric field at this point is oriented vertically, like the antenna. The magnetic field is perpendicular to both the electric field and the direction the EM waves travel, so the magnetic field must be oriented east-west. 6. Strategy and Solution At a point due north of the transmitter, the EM waves are traveling due north. The electric field at this point is oriented vertically, like the antenna. A receiver should be oriented the same as the transmitter, so the orientation of the receiver should be vertical. CHAPTER 22 PROBLEMS: [12], [15], 17, 19, 27, 32 12. Strategy The frequency, wavelength, and speed of EM radiation are related by . f c λ = Solution Compute the wavelength of the radio waves. 8 6 3.00 10 m s 3.3 m 90.9 10 Hz c f λ × = = = × 15. Strategy The speed of light in matter is given by , v c n = where n is the index of refraction. Solution Compute the index of refraction of topaz. 8 8 3.00 10 m s 1.62 1.85 10 m s c n v × = = = × 17. Strategy The time of travel is equal to the distance traveled divided by the rate of travel. Solution Compute the time it takes for light to travel 50.0 cm. 2 9 8 50.0 10 m 1.67 10 s 1.67 ns 3.00 10 m s d t c × Δ = = = × = × 19. (a) Strategy The wavelength is shorter in matter than it is in vacuum. Use Eq. (22-5). Solution Compute the wavelength of light inside the glass. v g 692 nm 455 nm 1.52 n λ λ = = = (b) Strategy The frequency in glass is the same as the frequency in air. Use . c f λ = Solution Compute the frequency of light inside the glass. 8 14 g a 9 a 3.00 10 m s 4.34 10 Hz 692 10 m c f f λ × = = = = × × 27. Strategy The electric and magnetic fields oscillate with the same frequency, and their amplitudes are proportional to each other. Use Eq. (22-6).
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