Pre-Calc Homework Solutions 19

# Pre-Calc Homework Solutions 19 - Section 1.4 2 y 3 x 2 0 we...

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2. y 52 4 3. x 5 2 4. When y 5 0, we have } x 9 2 } 5 1, so the x -intercepts are 2 3 and 3. When x 5 0, we have } 1 y 6 2 } 5 1, so the y -intercepts are 2 4 and 4. 5. When y 5 0, we have } 1 x 6 2 } 5 1, so the x -intercepts are 2 4 and 4. When x 5 0, we have 2} y 9 2 } 5 1, which has no real solution, so there are no y -intercepts. 6. When y 5 0, we have 0 5 x 1 1, so the x -intercept is 2 1. When x 5 0, we have 2 y 2 5 1, so the y -intercepts are 2} ˇ 1 2 w } and } ˇ 1 2 w } . 7. (a) 2(1) 2 (1) + 1 2 0 3 3 5 3 Yes (b) 2( 2 1) 2 ( 2 1) 1 ( 2 1) 2 0 3 2 2 1 1 0 3 2 1 ± 3 No (c) 2 1 } 1 2 } 2 2 ( 2 2) 1 ( 2 2) 2 0 3 2 1 1 4 0 3 3 5 3 Yes 8. (a) 9(1) 2 2 18(1) 1 4(3) 2 5 27 9 2 18 1 36 0 27 27 5 27 Yes (b) 9(1) 2 2 18(1) 1 4( 2 3) 2 0 27 9 2 18 1 36 0 27 27 5 27 Yes (c) 9( 2 1) 2 2 18( 2 1) 1 4(3) 2 0 27 9 1 18 1 36 0 27 63 ± 27 No 9. (a) 2 x 1 3 t 52 5 3 t 52 2 x 2 5 t 5 } 2 2 x 3 2 5 } (b) 3 y 2 2 t 52 1 2 2 t 52 3 y 2 1 2 t 5 3 y 1 1 t 5 } 3 y 2 1 1 } 10. (a) The equation is true for a \$ 0. (b)
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## This note was uploaded on 10/05/2011 for the course MAC 1147 taught by Professor German during the Spring '08 term at University of Florida.

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