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Unformatted text preview: 36 Chapter 1 Review
4 x 3 46. Since tan x has period , tan (x ) tan x . This function has period . A graph shows that no smaller number works for the period. 9. Since 4x 3y 12 is equivalent to y 4, the slope of the given line (and hence the slope of the desired line) is y y
4 (x 3 4 x 3 4 . 3 4)
20 3 12 [ 2 , 2 ] by [ 1, 5] 2 47. The period is 60 10. Since 3x
30 5y 1 is equivalent to y
3 5 . One possible graph: the given line is
5 . 3 3 x 5 1 , 5 the slope of and the slope of the perpendicular line is y y
60 60
, by [ 2, 2]
1 . 30 5 (x 3 5 x 3 1 2 2)
19 3 1 y 3 3 2 48. The period is 60 11. Since x One possible graph: 1 is equivalent to y
3 2 3 x 2 3, the slope of the given line is line is . y y
2 (x 3 2 x 3 2 3 and the slope of the perpendicular 1)
8 3 2 1 1 , by [ 2, 2] 60 60 12. The line passes through (0, m y 13. m
0 ( 5) 3 0 5 3 5) and (3, 0) s Chapter 1 Review Exercises (pp. 5253)
1. y y 2. y y 3. x 4. m y y 5. y 6. m y y 7. y 2
5 3 2 2 3 5 2 (x 3) 3 5 2 21 5 5 2 5 3(x 3x
1 (x 2 1 x 2 1) 9 1)
3 2 ( 6) 5 x 3 5
2 4 ( 2)
1 (x 2 1 x 2 2 2 4 1 2 2 f (x) f (x) 2) 3 4 0
2 1 6 ( 3) 8 4 Check: f(4) 2 1 (4) 2 3 1, as expected. 2) and ( 3, 0). 14. The line passes through (4, m y y 15.
0 ( 2) 3 4 2 (x 4) 7 2 6 x 7 7 2 7 2 7 2(x 2x 3) 6 2 3x 3 16. [ 3, 3] by [ 2, 2] 8. Since 2x y 2 is equivalent to y 2x 2, the slope of the given line (and hence the slope of the desired line) is 2. y 2(x 3) 1 y 2x 5 Symmetric about the origin. [ 3, 3] by [ 2, 2] Symmetric about the yaxis. ...
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This note was uploaded on 10/05/2011 for the course MAC 1147 taught by Professor German during the Spring '08 term at University of Florida.
 Spring '08
 GERMAN
 Slope

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