This preview shows page 1. Sign up to view the full content.
31. (a)
True
(b)
True
(c)
False, since lim
x
→
0
2
f
(
x
)
5
0.
(d)
True, since both are equal to 0.
(e)
True, since (d) is true.
(f)
True
(g)
False, since lim
x
→
0
f
(
x
)
5
0.
(h)
False, lim
x
→
1
2
f
(
x
)
5
1, but lim
x
→
1
f
(
x
) is undefined.
(i)
False, lim
x
→
1
1
f
(
x
)
5
0, but lim
x
→
1
f
(
x
) is undefined.
(j)
False, since lim
x
→
2
2
f
(
x
)
5
0.
32. (a)
True
(b)
False, since lim
x
→
2
f
(
x
)
5
1.
(c)
False, since lim
x
→
2
f
(
x
)
5
1.
(d)
True
(e)
True
(f)
True, since lim
x
→
1
2
f
(
x
)
±
lim
x
→
1
1
f
(
x
).
(g)
True, since both are equal to 0.
(h)
True
(i)
True, since lim
x
→
c
f
(
x
)
5
1 for all
c
in (1, 3).
33.
y
1
5
}
x
2
x
1
2
x
1
2
2
}
5
}
(
x
2
x
1
2
)(
x
1
1
2)
}
5
x
1
2,
x
±
1
(c)
34.
y
1
5
}
x
2
x
2
2
x
1
2
2
}
5
}
(
x
1
x
1
2
)(
x
1
2
2)
}
(b)
35.
y
1
5
}
x
2
2
x
2
2
x
1
1
1
}
5
}
(
x
x
2
2
1
1
)
2
}
5
x
2
1,
x
±
1
(d)
36.
y
1
5
}
x
2
x
1
1
x
1
2
2
}
5
}
(
x
2
x
1
1
)(
x
1
1
2)
}
(a)
37.
Since int
x
5
0 for
x
in (0, 1), lim
x
→
0
1
int
x
5
0.
38.
Since int
x
52
1 for
x
in (
2
1, 0), lim
x
→
0
2
int
x
1.
39.
Since int
x
5
0 for
x
in (0, 1), lim
x
→
0.01
int
x
5
0.
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 10/05/2011 for the course MAC 1147 taught by Professor German during the Spring '08 term at University of Florida.
 Spring '08
 GERMAN

Click to edit the document details