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Unformatted text preview: 36. (a) } f (1 1 h h ) 2 f (1) }5 } 2 1 1 h h 2 2 } (b) [ 2 4, 4] by [ 2 1, 5] Limit < 1.386 (c) They’re about the same. (d) Yes, it has a tangent whose slope is about ln 4. 37. Let f ( x ) 5 x 2/5 . The graph of y 5 } f (0 1 h h ) 2 f (0) }5} f ( h h ) } is shown. [ 2 4, 4] by [ 2 3, 3] The left and righthand limits are 2‘ and ‘ , respectively. Since they are not the same, the curve does not have a vertical tangent at x 5 0. No. 38. Let f ( x ) 5 x 3/5 . The graph of y 5 } f (0 1 h h ) 2 f (0) }5} f ( h h ) } is shown. [ 2 4, 4] by [ 2 3, 3] Yes, the curve has a vertical tangent at x 5 0 because lim h → } f (0 1 h h ) 2 f (0) }5‘ . 39. Let f ( x ) 5 x 1/3 . The graph of y 5 } f (0 1 h h ) 2 f (0) }5} f ( h h ) } is shown. [ 2 4, 4] by [ 2 3, 3] Yes, the curve has a vertical tangent at x 5 0 because lim h → } f (0 1 h h ) 2 f (0) }5‘ . 40. Let f ( x ) 5 x 2/3 . The graph of y 5 } f (0 1 h h ) 2 f (0) }5} f ( h h ) } is shown....
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This note was uploaded on 10/05/2011 for the course MAC 1147 taught by Professor German during the Spring '08 term at University of Florida.
 Spring '08
 GERMAN
 Limits

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