chem1211 hw 10 - 1. Convert 574.5 mmHg to atm, torr, Pa,...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
1. Convert 574.5 mmHg to atm, torr, Pa, and kPa. (1 atm = 1.01325 x 10 5 Pa) 0.7559 atm 574.5 torr 76592.0 Pa 76.59 kPa 574.5 mmHg x (1atm/760 mmHg) = 0.7559 atm 574.5 mmHg = 574.5 torr 0.7559 atm x (101325Pa/1atm) = 76592 Pa 76592Pa x (1kPa/1000Pa) = 76.59 kPa 2. A balloon that containes 1.40 liters of air at 725 torr is taken under water to a depth at which the pressure is 2.68 atm. Calculate the new volume of the balloon. Assume the temperature remains constant. 0.498 L First, change 725 torr to atm 725 torr x (1 atm / 760 torr) = 0.954 atm V 2 = P 1 V 1 /P 2 = (0.954 atm) x (1.40 L) / (2.68 atm) = 0.498 L 3. A 51.0 L sample of gas collected in the upper atmosphere at a pressure of 52.9 torr is compressed into a 165.0 mL container at the same temperature. What is the new pressure in atm? 21.5 atm To what volume would the original sample have had to be compressed in order to exert a pressure of 10.0 atm? 355.0 mL Use Boyle's Law: P = [52.9torr x (1atm/760torr) x 51.0 L]/[165.0 mL x (1L/1000mL)]
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 10/05/2011 for the course CHEM 1211 taught by Professor Atwood during the Spring '07 term at University of Georgia Athens.

Page1 / 2

chem1211 hw 10 - 1. Convert 574.5 mmHg to atm, torr, Pa,...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online