fall 10 test 4

# fall 10 test 4 - Version 051 Quiz 4 Coker(56625 This...

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Version 051 – Quiz 4 – Coker – (56625) 1 This print-out should have 24 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. This quiz covers the simple harmonic oscil- lator, waves, sound, and static and dynamic systems oF liquids and gases. None oF this ma- terial will be re-covered on the ±inal Exam. 001 10.0 points An incompressible ²uid is ²owing through a horizontal tube which, at some point has a constriction such that the area oF the tube becomes much smaller. B A How do the ²uid pressure and speed oF ²ow compare at point B in the constricted region to their values at point A in the normal part oF the tube? 1. The pressure and speed oF ²ow are both much greater at point A than at point B . 2. Because the ²uid is incompressible, the pressure and speed oF ²ow must be constant throughout the tube. 3. At point B ,thespeedo F²owislessbut the pressure is greater than at point A . 4. At point A ,thespeedoF²owislessbutthe pressure is greater than at point B . correct 5. The pressure and speed oF ²ow are both much greater at point B than at point A . Explanation: Since Av =constan t F²owat point B must be much greater than at point A .App ly ingBernou l l i ’spr inc ip le , P + 1 2 ρv 2 =constant , but the speed at point B is greater, so the pressure at B is much less than the pressure at A . 002 10.0 points AsimplependulumoFmass m and length ( is attached to a horizontal spring oF Force con- stant k and negligible mass that is tethered on the other end to a wall. When the pen- dulum hangs straight down in gravitational equilibrium, the spring is unstretched. IF the pendulum is displaced a very slight distance to the right, one can assume that its sim- ple harmonic motion has a period oF the Form T = 2 π e . θ m k What is the value oF the constant e ? 1. gk (m 2. k + g m( 3. 1 2 ± g ( + k m ² 4. The pendulum cannot be a simple har- monic oscillator because gravity will be the dominant Force on it, and gravity over such a short distance is a constant Force. 5. k (mg 6. Zero; the Force due to the spring cancels out the Force due to gravity. 7. g ( ,asalwaysForasimp lependu lum. 8. g ( - k m

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Version 051 – Quiz 4 – Coker – (56625) 2 9. k m + g ( correct Explanation: For very small oscillations, sin θ θ and x = ( sin θ .C o n s i d e r i n g t h e t o r q u e s about the pivot, ± τ i = - ( ( k Δ x ) - ( ( mg sin θ ) I p α = - ( ( k(θ + mgθ ) m( 2 α = - ( k( + ) α ≈- ² k m + g ( ³ θ = - ω 2 θ ω 2 = k m + g ( The period is T = 2 π ω = 2 π e , so e = k m + g ( . 003 10.0 points Blood fows through a coronary artery that is partially blocked by deposits along the artery wall. blood flow Through which part o± the artery is the fux (mass o± blood per unit time) largest? 1. The fux is the same in both parts. cor- rect 2. The wide part 3. The narrow part Explanation: Because blood is incompressible, the fux ±or a constant fow does not change.
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fall 10 test 4 - Version 051 Quiz 4 Coker(56625 This...

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